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A 5.00 kg box sits on a ramp that is inclined at 37.3 ∘ above the...

A 5.00 kg box sits on a ramp that is inclined at 37.3 ∘ above the horizontal. The coefficient of kinetic friction between the box and the ramp is 0.27. What horizontal force is required to move the box up the incline with a constant acceleration of 4.30 m/s2 ?

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Answer #1

The kinetic friction force on the inclined plane is, (0.37) (5.00 kg)(9.8 m/s)(cos37.3) = 10.5 N The net force on the box inc

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