Question

frequencies for the two loci in the three populations. Allele Locus PGM a Bayonne 0.1 0.8 0.1 Stamford 0.0 0.9 0.1 New Le 0.0 1.0 0.0 b с PGI-2 a 0.7 0.3 0.0 1.0 0.6 0.4 b 11. Using Hardy-Weinberg assumptions, which population should have the highest frequency of heterozygotes at PGI-2: a. Bayonne b. Stamford c. New Lebanon d. can't say from the data given 12. Using Hardy-Weinberg assumptions, identify the frequency of heterozygotes at PGM in New Lebanon: a. 0.00 b. 0.25 c. 0.50 d. 0.75 e. 1.00 13. Migration of individuals from Bayonne to Stamford would probably genetic variation at Stamford. a. decrease b. increase c. not affect 14-19. Using Hardy-Weinberg assumptions, list all the expected genotypes for PGM at Bayonne, and indicate their expected frequencies. You need not compute the actual values of the frequencies—just clearly indicate an expression for each. Genotypes:

please answer 11-19...
thank you!!

also calculate the frequencies for each genotype and phenotype!!

Answer 1

11)

c. New Lebanon

The frequency of heterozygotes for the PGI-2 locus is given by 2pq, where p and q are the frequencies for the a and the b alleles. For the Bayonne population, the frequency of Heterozygotes is 2 * 0.7 * 0.3 = 0.42. For the Stamford population the heterozygote frequency is 0.0 and for the New Lebanon population, the heterozygote frequency is 0.48.

12.

a. 0.00

Given that at the PGM locus, individuals of the population in New Lebanon only have the b allele, the frequency of heterozygotes is 0, becuase apart from the frequehncy of the allele b, the frequency of allele a and allele c for this population is 0.

13.

b. increase

Given that the Stamford population only has one allele for either locus, introduction of indivduals from the Bayonne population to the Stmford population would increase the genetic variation at stamford.

14 - 19)

For the Bayonne Population
a) PGM locus

Freq(a) allele = p = 0.1
Freq(b) allele = q = 0.8
Freq(c) allele = r = 0.1

Possible genotypes and their frquencies:
Freq(aa) = p2 = 0.1 * 0.1 = 0.01
Freq(ab) = 2pq = 2 * 0.1 * 0.8 = 0.16
Freq(ac) = 2pr = 2 * 0.1 * 0.1 = 0.02
Freq(bb) = q2 = 0.8 * 0.8 = 0.64
Freq(bc) = 2qr = 2 * 0.8 * 0.1 = 0.16
Freq(cc) = r2 = 0.1 * 0.1 = 0.01

b) PGI-2 locus

Freq(a) allele = p = 0.7
Freq(b) allele = q = 0.3

Possible genotypes and their frquencies:
Freq(aa) = p2 = 0.7 * 0.7 = 0.49
Freq(ab) = 2pq = 2 * 0.7 * 0.3 = 0.42
Freq(bb) = q2 = 0.3 * 0.3 = 0.09

For the Stamford population

a) PGM locus

Freq(a) allele = p = 0.0
Freq(b) allele = q = 0.9
Freq(c) allele = r = 0.1

Possible genotypes and their frquencies:

Freq(bb) = q2 = 0.9 * 0.9 = 0.81
Freq(bc) = 2qr = 2 * 0.9 * 0.1 = 0.18
Freq(cc) = r2 = 0.1 * 0.1 = 0.01

b) PGI-2 locus

Freq(a) allele = p = 0.0
Freq(b) allele = q = 1.0

Possible genotypes and their frquencies:

Freq(bb) = q2 = 1.0 * 1.0 = 1.0

For the New Lebanon Population
a) PGM locus

Freq(a) allele = p = 0.0
Freq(b) allele = q = 1.0
Freq(c) allele = r = 0.0

Possible genotypes and their frquencies:

Freq(bb) = q2 = 1.0 * 1.0 = 1.0

b) PGI-2 locus

Freq(a) allele = p = 0.6
Freq(b) allele = q = 0.4

Possible genotypes and their frquencies:
Freq(aa) = p2 = 0.6 * 0.6 = 0.36
Freq(ab) = 2pq = 2 * 0.6 * 0.4 = 0.48
Freq(bb) = q2 = 0.4 * 0.4 = 0.16