Question

In (Figure 1) a 6.00-m-long, uniform beam is hanging from a point 1.00 m to the right of its center. The beam weighs 160 N and makes an angle of 30.0 with the vertical. At the right- hand end of the beam a 100.0 N weight is hung; an unknown weight w hangs at the left end. Part A If the system is in equilibrium, what is w? You can ignore the thickness of the beam. Express your answer with the appropriate units. HA ? W= Value Units Submit Request Answer Part B Figure < 1 of 1 If the beam makes, instead, an angle of 45° with the vertical, what is w? Express your answer with the appropriate units. tu 007 HA ? Value Units 100.0 N 4.00 m Submit Request Answer 30.0° Provide Feedback и

Answer 1

Answer 2

Ni F.B.D of problem 42m rim С. loon 3m 30 16oN Ni is normal from linge point w A system is in equilibrium, we went to find wo in equilibrium z Exif extema) foyees Zext SO So, Wt 1000 +160 IN for que about hinge Now, point Zva 20 t t JOON Tuni How t 2150 kem 12:2) 1004 100(-6) + 0 + 11160).LCA) o 150 + 4 W.Ş CÂ) 2 so, -100K +80 Å tzw ico 2ฟ 20 Walon Weight 160 w is equal to Tool

B ) Now Nous then Again Herque about hinge point. Zoon + Yoon and + + TN zo N Ibon Tev 2. 100 (-k) re +o+ I (160) (Á) + 4W 1 (A) 20 22 V2 >> 200 +160 t 4W 2O 4W = 40 W =10 So, Megan w=low