mole of N2 released per L of blood = (2.142 * 10^-3 - 5.35 * 10^-4) = 1.607 * 10^-3 mole.
ideal gas equation is
PV = nRT
or
V = nRT / V = (1.607 * 10^-3 mole * 0.0821 L-atm/mole-K * 310 K) / 1.0 atm
or
V = 0.0409 L = 40.9 ml = 41 ml
thus
option (c) 41.0 ml is the answer.
At ardhacy bedy tenmpatue (37 te salublty of N water at cantains 5.35Xo mal af Na...