Question

Mass unknown halide mixture: Dilution volume for this preparation: Volume of this solution used for each trial: 0.7008 grams

What is the molarity of the silver nitrate titrant?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Given, W = 1.454 gr mw= V= M = 7 169.8731 g/mol 100 ml Molarity = WX 1000 I move = = 0.08559 0.086 Mthank you vmuch.....

Add a comment
Know the answer?
Add Answer to:
What is the molarity of the silver nitrate titrant? Mass unknown halide mixture: Dilution volume for...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • What is the molar concentration of a silver nitrate titrant if 42.51 mL of the titrant...

    What is the molar concentration of a silver nitrate titrant if 42.51 mL of the titrant are required to reach the endpoint when testing 0.524 g of sodium chloride standard (58.443 g/mol)? AgNO3(aq) + NaCl(aq) --> AgCl(s) + NaNO3(aq)

  • Exact molarity of 1M NaOH used is 1.083M, the volume of NaOH used is 10.0mL, the...

    Exact molarity of 1M NaOH used is 1.083M, the volume of NaOH used is 10.0mL, the final volume of stock NaOH is 100.00mL, and the molarity of stock NaOH solution is 0.1083M. KHP had a molar mass of 204.2 g/mole. acid base titration, part A B. Titration of KHP 1. 2. 3. Mass of KHP Initial buret reading Final buret reading Trial 1 Trial 2 0.30T usly & 0.00ml D.DD_ml 15.3 L 142 ml t is 1/0 ml _mol mol...

  • You obtain an unknown with an approximate chloride mass% of 51%. Calculate the volume (in mL)...

    You obtain an unknown with an approximate chloride mass% of 51%. Calculate the volume (in mL) of 0.29M silver nitrate you need to add to 0.2915 grams of unknown to ensure full precipitation. Your calculation should assume that you add 28% excess silver nitrate. Give the answer with the appropriate number of significant figures and the correct units. Silver nitrate molar mass: 169.87 g/mol Chloride molar mass: 35.45 g/mol

  • Calculate the volume in m) of silver nitrate solution that will be needed for the precipitation:...

    Calculate the volume in m) of silver nitrate solution that will be needed for the precipitation: normally the amount of silver nitrate required to precipitate all of the chloride in the sample is found by a trial and error process. However, to speed up the experiment, assume a sample mass of 0.1479 g, and that sample contains approximately 55.0% chloride ion by mass (some samples may contain more, some less), and calculate what volume of 0.100 M AgNO3 needs to...

  • a mixture is created of 306.0 grams of sodium nitrate, NaNO3, and 500 gram of water,H2O,...

    a mixture is created of 306.0 grams of sodium nitrate, NaNO3, and 500 gram of water,H2O, at 20 celcius . The density of the mixture is 1.30 G/ML. EXPRESS THE concentration of sodium nitrate as mass percent, molarity, molality, and mole fraction. Determine the freezing point, boiling point and osmotic pressure of the solution

  • Question 1 According to the following reaction, what mass of silver nitrate would be required to...

    Question 1 According to the following reaction, what mass of silver nitrate would be required to react with 0.500 grams of potassium chloride? AgNO3 (aq) + KCl (aq) --> AgCl (s) + KNO3 (aq) options 2.68 g 0.500 g 85.0 g 170 g 1.14 g Question 2 Consider the reaction: Na2CO3 (aq)+ 2 HCl (aq) --> 2 NaCl (aq) + CO2 (g) + H2O (l) If 43.41 g of sodium carbonate react completely, how many grams of HCl will be...

  • B. Determination of the Molarity of Unknown Acid Trial 1 Trial 2 Trial 3 Mass of...

    B. Determination of the Molarity of Unknown Acid Trial 1 Trial 2 Trial 3 Mass of Erlenmeyer flask (g) 124 g Mass of Erlenmeyer flask+acid After adding 5 mL HCl solution (g) 135 g Mass of HCl solution (g) Mass of HCl solution (kg) -------- ------ -- Volume (acid), mL ----5mL------- -----5 mL--- ------5mL---- NaOH Initial Volume (Vi) 0.00 mL ------------mL -------------mL NaOH final Volume (VA) 16.5 mL ----------- -------------m L ml ---------mL NaOH Volume Used Vi-Vi --------mL L

  • What is the percent by mass of HC7H5O3 in the unknown? A volume of 13.78 ml_...

    What is the percent by mass of HC7H5O3 in the unknown? A volume of 13.78 ml_ of 0.1010 M NaOH solution was used to titrate a 0.662 g sample of unknown containing HC7H5O3. What is the molecular mass of HC7H5O3? (report answers to 4 or 5 significant figures) 1.3812X10_2 g/mol What is the percent by mass of HC7H5O3 in the unknown? In this problem what mass of sample in grams would be needed to deliver about 22.50 ml_ in the...

  • Since you know the molarity of the NaOH titrant and the volume added to the equivalence...

    Since you know the molarity of the NaOH titrant and the volume added to the equivalence point, as well as the volume of acid used (10.00 mL) and the mole:mole ratio of acid and base, determine the molarity of the known and unknown acids. (You did this calculation in a 1211L, General Chemistry I, experiment.) molarHy of NoOH-O.118 Volume odd volume used - 10 Ratio Acetic Acid Molarity 27.1 (2 pts.) Unknown Acid Molarity (2 pts.) Show calculations for the...

  • A silver nitrate solution contains 14.77 g of primary standard AgNO, in 1.00 L. What volume...

    A silver nitrate solution contains 14.77 g of primary standard AgNO, in 1.00 L. What volume of this solution will be needed to react with a 0.1791 g of NaCl? Volume - 36.25 ml Correct Correct b 0.1791 g of Na, Croc? Volume mL C 69.15 mg of Na, AsO.? Volume mL d 353.5 mg of BaCl - 2H,0? Volume = ml e 25.00 mL of 0.04685 M Na PO? Volume 9.85 X mL

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT