Question

A silver nitrate solution contains 14.77 g of primary standard AgNO, in 1.00 L. What volume of this solution will be needed to react with a 0.1791 g of NaCl? Volume - 36.25 ml Correct Correct b 0.1791 g of Na, Croc? Volume mL C 69.15 mg of Na, AsO.? Volume mL d 353.5 mg of BaCl - 2H,0? Volume = ml e 25.00 mL of 0.04685 M Na PO? Volume 9.85 X mL

Answer 1

Moles o AgNO3 taken =- i 14.77 g - = 8.695 x162 mol 169.87 g/mol :. Molarity of thie Agnoz solution = 1 L = 8.695x10²m 8.695x10?mol the AgNO3 solution - NaCl + AgNO3 → NaNO3 + Aga Moles o Nad taken = _0.1791 9 z 3.065x103 mol Taken = 58.44 g/mol os According to reaction we striehiometry - Moles obs Ag Noz required - moles of Nace taken = 3,065 x103 mol 3,065 x103 mol Volum lume of Agnoz Tequired 8.695x102 mol/L = 0.03525 L = 35.25 mL (:11= 1000 mL) page-D

2 AgNO3 + Na, Croy → Ag2G0q + 2NaNO3 Moles of Nas Coroas taken - 0.17919 = 1.106x16°mal 161.97 g/mol . Moles of Agnoz nequined = 2X1.106x16 mol :Volume of AgNO3 Mequined =- ed- 2X1.106 XIo^mol x1000 m 8.695 x162 mol/L 1. = 125.44 mL c) 3 AgNO3 + Naz Asoq Agz4s0q + 3 NaNO3 Moles of Naz AsOy taken = - 69.15*10*7 3.326x104 mor 207.59 g/mol .. Moles ob AgNO3 requined = 3x 3.326x109 mol 3x3.326X164 1. Volume of AgNg requined z X1000 ml 81695 X10-2 = [11.48 mL (page-2

d) 2AgNO3 + Bach 24,0 > Ba(NO3)2 + 2Agu +240 Moles of Bact, 24,0 taken - 353.5 x100 g _ www.zx16 mol les opp bagzzle taken 244.26 g/mol 24 :. Moles ob AgNO3 requined = 2x1.447 X1ő mol ::. Volume of Agnoz Mequined a 23 Tequired, 2X1447x103 8.695x162 X1000 ml – 33.28) mL e) 3 AgNO3 + Naz pou — 3NaNO3 + Aga pog Mcles of Nazpoq taken = 0.0 en 0.74685 mol x 25.00 mL 1000 ml = 1,171x10 mol ;. Moles ou Agnez Mequined = 3X1.171x162 mol 3X1.1 .: Volume of Agnos required @ 3X1171x16 X1000 ml X1000 me 8.695x10-2 = 140.40 mL (page-3