no of moles of N2 nN2 = W/G.M.Wt = 10/28 = 0.357 moles
no of moles of O2 nO2 = W/G.M.Wt = 10/32 = 0.3125 moles
no of moles of C2H2 nC2H2 = W/G.M.Wt = 10/26 = 0.384 moles
mole fraction of XN2 = nN2 /nN2 + nO2 + nC2H2
= 0.375/0.375+0.3125+0.384
= 0.375/1.0715 = 0.349
mole fraction of XO2 = nO2 /nN2 + nO2 + nC2H2
= 0.3125/0.375+0.3125+0.384
= 0.3125/1.0715 = 0.292
mole fraction of XC2H2 = nC2H2 /nN2 + nO2 + nC2H2
= 0.384/0.375+0.3125+0.384
= 0.384/1.0715 = 0.358
D. >>> answer
A mixture of gas consists of 10 g N_2, 10 g O_2, and 10 g C_2H_2....
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