How do you calculate the moles of Cu(NO3) 2, show the steps!
Ans :
To calculate the number of moles of any compound , we divide the mass of sample by the molar mass of the compound.
The molar mass of Cu(NO3)2 is 187.56 g/mol
let the mass of compound sample be 100 g
so number of moles will be equal to :
moles = 100 g / 187.56 g/mol
= 0.533 moles
5. Calculate the number of moles of NO3 ions in 30.5 moles of Pb(NO3)2.
If 14.1 moles of Cu and 48.7 moles of HNO3 are allowed to react, how many moles of excess reactant will remain if the reaction goes to completion? 3 Cu + 8 HNO3 → 3Cu(NO3)2 + 2NO + 4H2O
What is reduced in the following reaction? Cu(NO3)2 + Zn -> Zn(NO3)2+ Cu ON O NO3 Zn O Cu(NO3)2
Any ideas on what results form when you mix HCl with Ba(No3)2 ,
Cu(No3)2, Fe(No3)3
or NH3 with Ba(No3)2 , Cu(NO3)2, Fe(NO3)3 or AgNO3?
1. Com HCL COM NH₃ AgNO3 White Precipitation Ba(NO3)2 Cu(NO3)2 Fe(NO3)3
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Homework 8 1. Calculate the number of moles of Mg(NO3)2 in 0.432 g of Mg(NO3)2. AND calculate the number of N and O atoms in the same amount of Mg(NO3)2-
If 14.4 moles of Cu and 17.4 moles of HNO3 are allowed to react, what is the maximum number of moles of NO that can be produced? 3 Cu + 8 HNO3 → 3Cu(NO3)2 + 2NO + 4H2O
data collected
Cu(NO3)2 | Zn(NO3)2 = 0.999 V
Pb | 1.0 M Pb(NO3)2 || 1.0 M Zn(NO3)2 | Zn = 0.396 V
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Sketch the galvanic cell based on a half-cell containing 0.1 M Cu(NO3)2 with a Cu(s) electrode and a half-cell containing 0.001 M Fe(NO3)2 with an Fe(s) electrode. Show the direction of electron flow and identify the cathode and the anode. Calculate Ecell and ∆G at 25 ◦C.