Question

How many mL of 0.265 M KMnO4 solution are needed to react with 4.42 g of...

How many mL of 0.265 M KMnO4 solution are needed to react with 4.42 g of iron
(II) sulfate?
2 KMnO4 + 10 FeSO4 + 8 H2SO4 –> 5 Fe2(SO4)3 + 2 MnSO4 + K2SO4 + 8 H2O
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Answer #1

molar mass of fe soy = 151.9089 mol moles of reson in 4.429 na 4.42g isi.9089/mol n= 0.0290 g mol na moles of KM nOn required

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