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2) B 20 с E A C 40 D As shown in the drawing above, a race follows a zig-zag path from A to B, then from B to D and finally f

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Answer #1

e (200-2) 20E С > where Accu A I E B (=com A E= 2oom Yo CD = you D Total length of the racecourse L= ABT BOT DE where AB=2 BDAB?? #?+ (2012 AB = Jocztyoo in ACED CE= AE - ACF 200-1 & using DE? = CE2+ CO2 (200-»)?+ (49)2 = Jisoot (200-vj? DEF Therefordl dre tor I (2x) 12+400 + - 2(200-n) 16004 (260-22 2 - Jx2+ You (200-n) J 16oot (200-ny? = x2(1600t (200-n) 2) = (100-vj? (xAlso dal duz z 이용 d du 200-1 [x?tyoo 1600+ (200-1)? d2L JAL 624400 = 222 x 24400 200-2) (244 (boot Roon? of Reo-n) x fonotAld at 자 200 1~)= J)4 100 +60+ 의 900t 60t1600t 2 200 0 [18+ ? () C 40000 + yoo looh) toog togt 2 역 S + 60t (6sor 60ooo g 19362 (208 201103 that yoslog 3 20slogt to to 3 L (200)= Length of face countee 26.8-8 meterLength of race course is longest 2(*)=fr 24400+ 6ot Jlroot (200-32 L(o)= Juoot bot lout 40000 20+60+ J41600L(o)=804 zoglou = 283-96 meter |(200)= |(200)24 + you t got Viboo Zoo.gg = 300.gg L(200) = Jyo yoo + 60+40 - loot Lo e should

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