Answer -
Given,
K2SO4 = 2.50 * 1023 units
Number of atoms produced = ?
_____ Pb + ______ K2SO4 ______ PbSO4 + _____ K
First Balance the reaction,
For Balancing a reaction make the number of atoms of each species equal on both side.
1 Pb + 1 K2SO4 1 PbSO4 + 2 K [BALANCED]
Now,
According to Avogadro's Law,
1 mole of anything have 6.022 * 1023 atoms, molecules or ions
i.e. 1 atom, molecule or ion is equal to (1/6.022 * 1023) mol
So,
2.50 * 1023 units of K2SO4 is equal to, 2.50 * 1023 * (1/6.022 * 1023) mol
So, moles of K2SO4 = 0.41514447027 mol
1 Pb + 1 K2SO4 1 PbSO4 + 2 K [BALANCED]
Using Stiochiometry,
It can be analyzed that for 1 mol of K2SO4, 2 moles of K are produced.
i.e. moles of K Produced = 2 * moles of K2SO4
So, Moles of K produced = 2 * 0.41514447027 mol = 0.83028894054 mol
Using Avogadro's Law,
1 mole = 6.022 * 1023 atoms
So, 0.83028894054 mol of K = 0.83028894054 * 6.022 * 1023 atoms = 4.99999999993 * 1023 atoms
So, Approx. 5 * 1023 atoms of K are produced [ANSWER]
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