How many oxygen atoms are on the reactant side of this chemical equation? K2SO4(aq)+Pb(NO3)2(aq)→2KNO3(aq)+PbSO4(s)

Question

Question

How many oxygen atoms are on the reactant side of this chemical equation?

K2SO4(aq)+Pb(NO3)2(aq)→2KNO3(aq)+PbSO4(s)

Answer 1

Answer #1

K₂SO₄(aq)+Pb(NO₃)₂(aq)→2KNO₃(aq)+PbSO₄(s)

oxygen atoms in K₂SO₄ = 4

oxygen atoms in Pb(NO₃)₂ = 6

Number of oxygen atoms on the reactant side = 10

Answer 2

Answer #2

How many oxygen atoms are on the reactant side of this chemical equation?

$2 K_{3} P O_{4} (a q) + 3 P b (N O_{3})_{2} (a q) \to 6 K N O_{3} (a q) + P b_{3} (P O_{4})_{2} (s)$

How many oxygen atoms are on the reactant side of this chemical equation?

8

17

26

44

answered by: kay

Answer 3

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