A force F = 1.8 i + 2.5 j N is applied at the point x = 3.0 m, y = 0 m.
(a) Find the torque about the origin.
k N
(a)F = 1.8 i + 2.5 j N
torque=(3 i)x(1.8 i + 2.5 j )=7.5 k N-m
(a)F = 1.8 i + 2.5 j N
torque=((3-(-1.3))i+(0-2.4))x(1.8 i + 2.5 j )=(4.3i - 2.4 j )x(1.8 i + 2.5 j ) = (4.32+ 10.75) k N-m=15.07 k N-m
A metal bar is in the xy-plane with one end of the bar at the origin. A force F =(6.12 N )i+(-3.27 N )j is applied to the bar at the point x = 2.07 m, y = 3.02 m. Part A What is the position vector for the point where the force is applied?Part B What is the magnitude of the torque with respect to the origin produced by F?
A 12-N force is applied at the point x=3m, y=1m. Find the torque about the origin if the force points in (a) the x direction, (b) the y direction, and (c) the z direction. Part A For example, for vector <1,1,1> enter i^+j^+k^. Part B For example, for vector <1,1,1> enter i^+j^+k^. Part C For example, for vector <1,1,1> enter i^+j^+k^.
A metal bar is in the xy-plane with one end of the bar at the origin. A force F =( 6.39 N )i +( -3.16 N )j is applied to the bar at the point x = 2.29 m, y = 3.19 m.A) What is the position vector r⃗ for the point where the force is applied?Enter the x and y components of the radius vector separated by a comma.*B) What is the magnitude of the torque with respect to...
A force F⃗ = 2.00 N i⃗ + 3.10 N j⃗ is applied at the point x = 3.20 m , y = 0.00 m . Find the torque about the origin due to the force F⃗ . Give the x, y, and z components. What is the torque due to the same force, applied at the same location, about the point x = -1.00 m , y = 3.10 m ? Give the x, y, and z components.
Force F = 1.99 N i -3.18 N k acts on a pebble with position vector T = 0.48 m J -2.20 m k relative to the origin What is the resulting torque on the pebble about the origin? Enter i, j, and k component. What is the resulting torque on the pebble about the point (2.12 m, 0, -3.32 m)? Enter i, j, and k component.
A force F = 61 N i acts on an object
at a point (x0, y0) = (6.2 m, 4.7
m) as shown in the figure. What is the magnitude of the
torque generated by this force about the origin?
What is the magnitude of the torque generated by this force
about the point (x, y) = (2.9 m, 1.6 m)?
Suppose the object is free to rotate about the z axis. If the
object has a moment of inertia...
1. (a) Force F = -21 - 4 (N) is applied to a metal bar in the x-y plane with one end of the bar at the origin. The point on the bar of application of the force is (x - 2m, y m). Use the position vector (1) of the point of action of the force to find the magnitude and direction of the torque. Hint: Employ method of determinant to find cross product (6pts) Show working (2pts) Magnitude...
Force = 2.11 N i -3.19 N k acts on a pebble with position vector = 0.51 m j -2.12 m k relative to the origin. What is the resulting torque on the pebble about the origin? Enter i, j, and k component. What is the resulting torque on the pebble about the point (2.02 m, 0, -3.25 m)? Enter i, j, and k component.
1. (a) Force F = -21 - 4 (N) is applied to a metal bar in the x-y plane with one end of the har at the origin. The point on the bar of application of the force is (x = -2m, y - 4m). Use the position vector (1) of the point of action of the force to find the magnitude and direction of the torque. Hint: Employ method of determinant to find cross product (6pts) Show working px...
A force is given by F = F_0 i + F_0 j. The force is applied at the position given by r = r_0 i - r_0 j. Find the torque r = r times F = ?