The valence electron configurations of several atoms are shown. How many bonds can each atom make without hybridization?
Part A
Mg: 3s2
part B
Cl: 3s23p5
Part C
Al: 3s23p1
Answer: Here we have to obseve that the bond formation without hybridization means there is no mixing
so In A] the 3S2 is full and there is no unpaired electrons hence in Mg : 3S2 there is no bond without hybridization
part B: Here we have one unpaired electrons and 3 lone pair and hence it can form 1 bond and 0 zero
part C: Al: 3S3P1 it has one lone pair and one unpaired electrons hence it can make 1 bond
The valence electron configurations of several atoms are shown. How many bonds can each atom make...
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