Question

water Pressure vs Depth - U Shaped Tube Two Fluids 2 As shown in the figures, a U-shaped tube open to the air at both sides contain some unknown liquid. Then water (density = 1000 kg/m 3) fills the Right arm of the U-tube (there is no intermixing between the two liquids). When equilibrium is reached, h1 = 0.18 m, and height of water h2 - 0.56 m. The atmospheric pressure is 1.013x105 Pa. What is the density of the unknown liquid? (a) Before solving for the density of the unknown fluid, Use your intuition: look at the figure and compare the heights of the two fluids, how do their densites compare? Select your answer from one the following options a density of unknown fluid Densty of water density of unknown fluid Densty of water density of unknown fluid Denty of water Corrent 100 M The most important step in solving a U-Shaped Tube problem is to identify two points (one on each side) that have the same pressure. These two points must be at the SAME HORIZONTAL Level in the SAME FLUID Points A and B in the figure on the right are at the same horizontal level and in the same fluid (unknown fluid). (Point B is also at the bottom of water) PA Pe Apply the pressure varying with depth equation to write PA in terms of density of unknown fluid (and other relevant quantities) and to write PB in terms of density of water and other relevant quantites. Solve for the density of the unknown fluid. (5 attempts remaining) What is the pressure at point A in 105 Pa? Keep 3 decimal places. For example, if the result is 123456 Pa = 1.23456x105 Pa, enter 1.235. x10Pa m (5 attempts remaining) What is the pressure at point B in 10 5 Pa? Keep 3 decimal places. XIOP

Answer 1

water Thr density of water Suater = 1000 kg/m3 hi=0018m ha= 0.56 m unknown (no intermixing) .: point A & B [same horizontal level & same fluid - unknown] 08 PA = PB [op=fgh]

hy height from upper surface of fluid " PA = PB Tunknown yg x Chr-hi) + Po = Pot Sw x 9 x hz → funknown = fw hotel 0.56 =10008 0056-0018 i density of unknown fluid Sunknown) = 1473.684 Kg 1m3 o density of unknowns density of water Peressure at point 'A' PA = Pot fw g hz o Po= 160138105 pa [ atmospheric pressure) APA = 100/3 x 16.5 + 103 x 9.8 x 0:56 =(20013 +0005488) x 105 PA = 1.06788 X 105 pa At Point 'B' PB = Po + Punknown xg x Cha-hi) = 1013X105 + 1473.684 x 9.8 XER 038 pressure . . PB = 1006788x105 pa