Answer 3:
It is given that I gene is showing dominant epistasis on B gene. I gene inhibits the expression of B gene.
A) bbii: Here brown phenotype is produced because ii and bb both are in recessive form.
BbIi: here I gene inhibit the B gene expression and brown color phenotype is seen.
Parents: bbii × BbIi
Punnet square:
Gametes | bi |
BI | BbIi ( brown) |
Bi | Bbii ( black) |
bI | bbIi( brown) |
bi | bbii ( brown) |
B) BbIi : brown because I inhibit the expression of B gene
Bbii: Black phenotype because I is in recessive form. That's why B gene encodes black phenotype.
Parents: BbIi × Bbii
Punnet square:
Gametes | Bi | bi |
BI | BBIi ( brown) | BbIi ( brown) |
Bi | BBii( black) | Bbii( black) |
bI | BbIi ( brown) | bbIi( brown) |
bi | Bbii (black) | bbIi( brown) |
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