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3) (2 pts) In a certain breed of dog, the dominant, B, is required for black fur; its recessive, b, produces brown fur. Howe
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Answer #1

Answer 3:

It is given that I gene is showing dominant epistasis on B gene. I gene inhibits the expression of B gene.

A) bbii: Here brown phenotype is produced because ii and bb both are in recessive form.

BbIi: here I gene inhibit the B gene expression and brown color phenotype is seen.

Parents: bbii × BbIi

Punnet square:

Gametes bi
BI BbIi ( brown)
Bi Bbii ( black)
bI bbIi( brown)
bi bbii ( brown)

B) BbIi : brown because I inhibit the expression of B gene

Bbii: Black phenotype because I is in recessive form. That's why B gene encodes black phenotype.

Parents: BbIi × Bbii

Punnet square:

Gametes Bi bi
BI BBIi ( brown) BbIi ( brown)
Bi BBii( black) Bbii( black)
bI BbIi ( brown) bbIi( brown)
bi Bbii (black) bbIi( brown)

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