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F (N) 10 marks 10 kg 50N--- 4 8 12 The 10-kg box, which was initially at rest, is subjected to the horizontal force F, where

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m= loky g= 9.81 m Ms = MK = 0.2 SON - - - - 0 Initially block is at rest (v=o). on 11 force f(t) is applied on block the willCalculating time when F(t) = Fs) max D 19.62 = 12.5t t= 1.5696 sec. Hence at t = 1.5696 block starts moving. at t= 1.5696 v=0V4 = 1.25 (42-45697) - 1.96264-1.5096) 16) - 1.96204-1.5696) V = 8. 4602 – 4.7684 V4 = 3.6917 m hence at t= 4 velocity VA is=Considering time interval 8 th 12 let force ear is F(t) = At + B where A and B are constant at t=8 F(t) = 50 50 = 8 A+B 0 ata = -1.25 t + 13.038 du= – 1.25t + 13.036 dt t=12 t=8 25t + 13.036) at ve te * Vier Vo = -1,25 [12²-82] + 13.038 (12-8) -50t

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