Question

hls help，how to do this question？thanks

QUESTION 3 Light of one particular wavelength is allowed to enter the surface of a diamond as shown in Figure 3. The refractive index of air and diamond is 1.0 and 2.4, respectively. (a) Calculate the angles x and y. (4 marks) (b) With the aid of calculations at surfaces CD, DE and AB, 0 show that angle y is greater than the critical angle of the diamond. (ii) state the light phenomenon when the light hits on surfaces CD, DE and AB. (ii) for the light phenomenon at surfaces CD and DE, state the two conditions that are required for this phenomenon to occur. (13 marks) (c) Redraw Figure 3 in your answer booklet and illustrate the path of the light in the diamond after hitting each surface, indicating the incident angles of the light path at the various surfaces (CD, DE and AB). (3 marks) 45° B. E C 38° i 38° D Figure 3

Answer 1

Ang a) According to snell's law u = sini sina 2.4 1.0 sin 45 sina Sina = sinus 2.4 sina = ve ay (43) x = sint n=17:40* x+y + 90 +38 = 180° 17.40 + y +90+ 38 =180 y = 180-(128 717.40) y = 34.60 b) ús critical angle = cosect 4 - (24) > 35° y s critical angle 34.6 > 25.45 it, The light phenomenon occurs when light hits on co, De and . AB is total internal reflection. (li, Two conductors for the total internal reflection to occur is. a) The angle of incidence is greater than the critical angle

bo light is in more dense medium and approaching towards the less densse medium, c ) A B C 1.38°90-346º. 486 Incidence angle at @ CD = 34.6. reflected angle at CD =346 Incidence angle at DE = 41,4° reflecteargle at DE 4149 Incidence angle at AE = 48.6°.