Homework Answers
KHP is acid and NaOH is base.
We have acid base reaction.
KHP + NaOH ---> H2O + K+(aq) + Na+ (aq) + P2-(aq)
so KHP and NaoH react in 1;1 ratio.
KH moles = mass of KHP / molar mass of KHP = 0.121 /204.2 = 0.00059255
Now NaoH moles = KHP moles = 0.00059255
Mollarity fo NaOH = moles of NaoH / volume of NaoH in L
M of NaoH = ( 0.00059255) / ( 0.0325) = 0.01823 M
thus concentrationof NaoH= 0.01823 M
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