State 1
By ideal gas equation
P1 V1 = ma R T1
100 * 5700/60 = ma * 0.287 * 480
ma = 68.9605 kg/s
State 2
400 K
State 3
300 kPa, 400C
h3 = 167.79 kJ/kg --- from compressed water table
s3 = 0.57229 kJ/kg-K --- from compressed water table
Heat lost by air = Heat gained by water
ma Cp (T1 - T2) = mw (h4 - h3)
68.9605 * 1.005 (480 - 400) = 2 (h4 - 167.79)
h4 = 2940.00 kJ/kg
State 4
300 kPa, h4 = 2940.00 kJ/kg
T4 = 2360C --- from superheated vapor table
s4 = 7.463 kJ/kg-K --- from superheated vapor table
State 5
5 kPa, x = 97%
hf = 137.75 kJ/kg , hg = 2560.7 kJ/kg --- from saturated pressure table
h5 = hf + x5 (hg - hf)
h5 = 137.75 + 0.97 (2560.7 - 137.75)
h5 = 2488.01 kJ/kg
sf = 0.47620 kJ/kg-K , sg = 8.3938 kJ/kg-K --- from saturated pressure table
s5 = sf + x5 (sg - sf)
s5 = 0.47620 + 0.97 (8.3938 - 0.47620)
s5 = 8.156272 kJ/kg
Wturb = mw (h4 - h5)
Wturb = 2 (2940.00 - 2488.01)
Wturb = 903.98 kW
SHX = S1-2 + S3-4
SHX = ma Cp ln (T2 / T1) + mw (s4 - s3)
SHX = 68.9605 * 1.005 ln (400 / 480) + 2 (7.463 - 0.57229)
SHX = 1.145569 kW/K
Sturbine = S4-5
Sturbine = mw (s5 - s4)
Sturbine = 2 (8.156272 - 7.463)
Sturbine = 1.386544 kW/K
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