A loundspeaker diaphragm is producing a sound for 2.5 s by moving back and forth in a simple harmonic motion. The angular frequency of the motion is 8.22 ✕ 104 rad/s. How many times does the diaphragm move back and forth
Angular frequency = 8.22*10^4 radian /second
Frequency = 8.22*10^4/2*π=1.30*10^4 hertz
Time period =1/ frequency
= 1/1.30*10^4
Total time = number of Period x Time period
2.5. = number of Period ×1/1.30*10^4
Therefore number of Periods
2.5 *1.30*10^4 = number of Periods
32,500 times the diaphragm move back and forth
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