Question

Which DNA primer would have the highest melting temperature? ATACAGATCGGC O ATACGCAGATCGGC O AATCGGAT O ACCGGCAGGTCGGC GCATCGGC

Answer 1

Option D is the correct answer.

Melting temperature is designated by Tm.

Melting point is calculated by the formula:

Tm = ( A + T ) * 2 + ( G + C ) * 4

Option D sequence ACCGGCAGGTCGGC

Sequence length - 14

No. of A = 2

No. of T = 1

No. of G = 6

No. of C = 5

Tm = ( A + T ) * 2 + ( G + C ) * 4

= ( 2 + 1) * 2 + ( 6 + 5 ) * 4

= 3 * 2 + 11 * 4

= 6 + 44

=

50°C

So, the highest melting temperature among the given options is option D and the sequence is ACCGGCAGGTCGGC.

Melting temperatures of other options are as follows:

Option A - Tm = $36^{o}C$

Option B - Tm = $44^{o}C$

Option C - Tm = $32^{o}C$

Option E - Tm = $28^{o}C$

All the melting temperatures are calculated in the same way as above.