When 50 people used the Weight Watchers diet for one year, their mean weight loss was 3.0 lb and standard deviation was 4.9lb. Assume that the population standard deviation is 5.0 lb. Use a 0.01 significance level to test the claim that the mean weight loss is greater than 1.5.
Find the null hypothesis and alternate hypothesis.
H0:
H1: p
When 40 people use the Weight Watchers diet for one year, their mean weight loss was 3.0 pounds. Historically the standard deviation is σ = 4.9 pounds (based on data from “Comparison of the Atkins, Ornish, Weight Watchers, and Zone Diets for Weight Loss and Heart Disease Reduction,” by Dansinger, et al., Journal of the American Medical Association, Vol. 293, No. 1). Use a 0.01 significance level to test the claim that the mean weight loss is greater than 0....
The null hypothesis and the alternate hypothesis are: H0: The frequencies are equal. H1: The frequencies are not equal. Category f0 A 25 B 20 C 25 D 10 1) State the decision rule, using the 0.01 significance level. Reject H0 if chi-square > _____ 2) Compute the value of chi-square.
13. When 40 people used the Weight Watchers diet for one year, their mean weight loss was 3.0 lb and the standard deviation was 4.9 lb. Use a 0.05 significance level to test the claim that the mean weight loss is greater than 0. Show graphing calculator command in the box below. Step 1: Claim: Step 2: Opposite of the Claim: Step 3: Ho: H: Step 4: a = 0.05 Step 5: Test Statistie: Step 6: P-value Step 7: Step...
Identify the null hypothesis. alternative hypothesis, test statistic, decision about the null hypothesis and final conclusion that addresses the original claim Various temperature measurements are recorded at different times for a particular city. The mean of 20 degrees is obtained for 60 temperatures on 60 different days. Assuming that the population standard deviation is 1.5 degrees, test the claim that the population mean is 22 degrees. Use a 0.05 significance level Hou = 22; H1 is u# 22 Test statistic:...
The null hypothesis and the alternate are H0: The frequencies are equal. H1: The frequencies are not equal. Category f0 A 15 B 10 C 10 D 15
Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. A test of sobriety involves measuring the subject's motor skills. A study of n = 20 randomly selected sober subjects take the test and produce a mean score of X = 41.0, and we know that o = 3.7. At the 0.01 level of significance, test the claim that the true mean score for all sober subjects is...
Each answer requires: The problem statement Assumptions The null and alternate hypothesis statements The significance level The test statistic (as an equation) Decision rules The calculated value of the test statistic The p-value Interpret the results of the test. When operating normally, a manufacturing process produces tablets for which the mean weight of the active ingredient is 5 grams, and the standard deviation is 0.025 gram. For a random sample of 12 tables the following weights of active ingredient (in...
Data on the weights (lb) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. Diet Regular muμ mu 1μ1 mu 2μ2 n 3838 3838...
The null and alternate hypotheses are: H0 : μ1 = μ2 H1 : μ1 ≠ μ2 A random sample of 11 observations from Population 1 revealed a sample mean of 21 and sample deviation of 3.5. A random sample of 7 observations from Population 2 revealed a sample mean of 23 and sample standard deviation of 3.8. The underlying population standard deviations are unknown but are assumed to be equal. At the .05 significance level, is there a...
Random samples of two species of iris gave the following petal lengths (in cm). x1, Iris virginica 5.1 5.9 4.5 4.9 5.7 4.8 5.8 6.4 5.7 5.9 x2, Iris versicolor 4.5 4.3 4.7 5.0 3.8 5.1 4.4 4.2 (a) Use a 5% level of significance to test the claim that the population standard deviation of x1 is larger than 0.55. What is the level of significance? State the null and alternate hypotheses. H0: σ = 0.55; H1: σ > 0.55...