A mixture of hydrogen and methane gases, at a total pressure of 912 mm Hg, contains...

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Answer 1

Answer #1

answer:

Given : total pressure=912 mmHg

Mass of H₂ =0.575g , Mass of CH₄= 2.02g

We know that no. of moles = mass/molar mass,. also

molar mass of H₂ =2.016g/mol and molar mass of CH₄=16.04g/mol

Now, moles of H₂=0.575/2.016=0.2852mol

moles of CH₄=2.02/16.04=0.1259mol

Since, Partial pressure=mole fraction*total pressure

Partial pressure of H₂= [0.2852/(0.2852+0.1259)]×912=632.6986=>P_H2=632.7mmHg

P_CH4= [0.1259/(0.1259+0.2852)]×912=279.301=>P_CH4=279.3mmHg

Answer 2

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