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A charge Q is located inside a rectangular box. The electric flux through each of the...

A charge Q is located inside a rectangular box. The electric flux through each of the six surfaces of the box is: ?1 = +1380 N

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Answer #1

flux ? = Q / ?o

where eo is permittivity of free space

Summing all the flux:

=>flux total=+1380 +2220 +4140 -1860 -3650 -5900= -3670 N

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Answer #2

dd up all the ?'s to get -2400, then use ?0?=Q

(-2400)(8.85x10^-12) = -2.124 x 10^-8 C

In this problem the total flux through the surface of the box is 0, so the electric charge inside it will be 0.

In your problem the total flux is non-zero so the charge inside will be non-zero.

This is exactly what Gauss' law is all about.

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Answer #3

net charge =net flux x e0

Q=( +1380 +2220 +4140 -1860 -3650 -5900)x 8.85x10-12

Q=-0.0325x10-6C

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