Question

Section Date Student Name Report on Laboratory Experiment "Measurements and Unit Conversions" LABORATORY ACTIVITIES: 1. Measuring length: la Using your body while pacing: This is a quick and easy method in the absence of another instrument. 1. Count how many steps it takes you to cover the 50 ft distance marked on the hall's floor. hamber of feet 2. Calculate your step size (p e sumber of steps). 3. Count how many steps it takes you to go from one end to the other end of the chalkboard. 4. Calculate the length of the chalkboard (Length (number of steps). (your step stre)). of steps for 50 ft Determination of length by pacing your step size # of steps for board (ft/step) (step) Length of board (step) 1b. Using a British measuring tape or ruler: Measure the length , width Wand height H of the shoebox shaped object and record them in inches plus fractions of an inch. Transform them to decimal format. Dimensions of shoebox shaped object measured with ruler Format length L width W height H In inches and fractions In decimal inches format (show your work)

Answer 1

1a) using your body to measure length.

I will calculate these things based on dimensions of my feet i.e. my step size.

The steps required by me to cross a 50ft distance are 43.

Therefore my step size is 50/43=0.86ft.

I chose a standard sized chalkboard. The number of steps required to traverse the length of the chalkboard=15

Therefore the length of the chalkboard=0.86×15=13ft

1b) using a British measuring tape or ruler

Format	L	W	H
In inches and fractions	12inches+3/25th inch	6 inch+7/50th inch	7inch+4/11th inch
In decimal inches	12.12inch One inch is almost 2.54cm. Therefore 1cm is 25/64th of an Inch=0.39inch 1mm=0.039inch Since 3/25th inch=0.12 Therefore 30.8cm=12.12inch	6.14inch Once again 1inch =2.54cm Therefore 15.6cm=15.6/2.54=6.14inch	7.36inch 1inch=2.54cm Therefore 18.7cm=7.36inch Also

1c) using a metric (SI) measuring tape or ruler.

Format	L	W	H
Centimetres+millimetres	30cm+8mm	15cm+6mm	18cm+7mm
Centimetres in decimal Format	30.8cm 1cm=10mm. Therefore 1mm=0.1cm. Therefore 8mm=0.8cm Therefore in decimal format 30cm+8mm=30.8cm	15.6cm Once again 1mm=0.1cm Therefore 6mm=0.6cm Therefore 15cm+6mm=15.6cm	Here 7mm=0.7cm Therefore 18cm+7mm=18.7cm

2a)the volume of shoebox

in_{​​​​​}^{​​​​​3}=12.12×6.14×7.36=547.70in³

cm^{​​​​​3}​​​​=30.8×15.6×18.7=8984.97cm³

2b) the volume of water used in this demonstration is 850ml

When the metal object was submerged in water the volume was 970ml. The volume increase occurs due to the volume of the metal ball which displaces water which is equal to its volume

Therefore the volume of the metal object was 970-850=120ml