Calculate Ea for a reaction having k = 2.61 x 10-5 at 190.0°C, and k = 3.02 x 10-3 at 250.0°C.
a. 2.56 x 105
b. 1.59 x 105
c. 39.5
d. 3.13 x 104
Calculate Ea for a reaction having k = 2.61 x 10-5 at 190.0°C, and k =...
107) What is the magnitude of k for a first-order reaction at 75.0 °C if Ea = 95.1 kl/mol and rate constant is 1.35 x 102 s-1 at 25.0 ℃? A) 1.36 x 10 B) 4.28 x 106 C) 3.85 104 D) 3.36 x 104 E) 745 108) Which of the followino exnressions is the correct equilibri
1) Calculate the activation energy (Ea) of a reaction having a rate constant of 1.78 X 10^-3 MS at 34.5C and a rate constant at 52C of 1.40x10^-2 MS. Could you please give step by step. Unsure of what to do after plugging numbers into the equation.
The equilibrium constant K for the reaction fructose-1,6-diphosphate, is 8.9 x 10-5 Mat 25°C and we can assume the behavior to be ideal. glyceraldehyde-3-phosphate + dihydroxyacetone phosphate a. Calculate AGº for the process (standard state: 1M) b. Suppose that we have a mixture that is initially 0.01M in fructose-1,6-diphosphate and 105 M in both glyceraldehyde-3-phosphate and dihydroxyacetone phosphate. What is AG? in which direction will the reaction occur?
Using the reduction potentials given, calculate the equilibrium
constant, K, at 20 degrees C for the reaction
Using the reduction potentials given, calculate the equilibrium constant, K, at 25°C for the reaction, 33 3+ Ag (aa) t Fe(a)Ag) Fe (aq) +0.77 V +0.80 V A Ag+(aq) + e- ← a. 1.66 b. 6.4 c. 3.2 d. 6.1 x 10-4 e. 1.6 x 104 Rank the following compounds according to increasing solubility in water. K” is a less than sign) 34...
Question 13 The value of the equilibrium constant for a reaction is 2.65 x 10-6 at 318 K. Calculate the value of AGºrx at this temperature. +4.74 x 104 +1.48 104) +3.39 104 +3.35 x 105) -1.48 x 103) < Previous
O KINETICS AND EQUILIBRIUM Using the Arrhenius equation to calculate Ea from k versus T data The rate constant k for a certain reaction is measured at two different temperatures: temperature 148.0°C 89.0 °C k 5.7 x 10° 3.3 * 10° Assuming the rate constant obeys the Arrhenius equation, calculate the activation energy E, for this reaction Round your answer to 2 significant digits.
KINETICS AND EQUILIBRIUM Using the Arrhenius equation to calculate Ea from k versus T data The rate constant k for a certain reaction is measured at two different temperatures: temperaturek 204.0 °C | 2.4 × 1010 333.0 °c 5.7 x 101 Assuming the rate constant obeys the Arhenius equation, calculate the activation energy Ea for this reaction. Round your answer to 2 significant digits. IP mol
9) The reaction 2C-D + E (K= 3.3 x 10-3) has [C]-0.05 M and [DHE]-5 x 10" M: a) is the reaction at equilibrium? b) if not, which way will it shift and what will the equilibrium concentrations be?
Calculate the activation energy of a reaction if the rate constant at 555 K is 3.72 times 10^-5 and at 761 K it is 2.95 times 10^-3. Calculate the rate constant at 70 degree C for the reaction A + 3B rightarrow 2C given that the rate constant of the reaction is equal to 3.5 times 10^-1 M^-4 s^-1 at 95 degree C. (Ea = 142 kJ/mol)
3. A reaction 2A 2B + C is known to follow second-order kinetics, with k = 7.20x10*M's' at 25.0 °C. (20 points) During one experiment, the initial concentration of A is [A]. = 0.120 M (a) Calculate the half-life (1,2), in hours, for this experiment. (b) Calculate the initial reaction rate (in M/s) for this reaction (4 points) (c) How long will it take (in hours) for the concentration of C to reach [C] = 0.0540 M (6 points) (d)...