Question

Determine the maximum power transfer to terminals ab 5Ω 10 Ω 25 V 0.51, 10Ω OD

Answer 1

Q Determine maximum power toansfer to terminals ab, 51 Tos 25V (40.55 136 - 06 To solve this type of questions you should find a&b terminals . Thevenin's equalent circuit across 1 Rtb vies! Voc = Uto ob Vab. * step ů - find With = Voc across a&b 52 los b ^ &5V V b sosie los vab "Fix Apply Nodal Analysis . while writing nodal equations Assume current flows out of the node shocon at Node à. Nab Voc Vt ů same as . node b' voltage. * write Nodal equations at Nodela'. va-V6 +0.5ix + va-25 5 10 aka-25) + 1000.5 ix) + va- Yes =0 V6=Utes 10 =O qua - 50 +58x tua -uth 34-50.45ix = With 1

* write Nodal equation at 'b'. 6-va + 10 10 V6-vatub 10 Qub=va = Va = QV46 th= olio Vb 3 = uth 10 - and ix ohm's law 3 substitute in equation - 8 (evtl.) - 50 + 50 vote) = Vth 6th t uth & = 50 -uth 50 Vith [6+1 -1] - th = 9.09 Volls 50 the 5.5= while one * Step at Find Rth finding Rts, Deactivate all independent sources present in circuit. Ccircuit has only independent voltage sources it should be short) .but do not change dependent Sources . b a 102 5» IT Rth= VT IT wo + UT Doosi, los Yix b external if circuit contains dependent Sources source ut which delivers It then find Conneet VT Rth IT Apply Nodal Analysis Va-Vb 5 =O: va toisin + 10 but | V6 =VT

Qua + 10x0.5lx + Va-Vr 10 Bra +5ix =VT - at Node i bl. 6-va 10 IT ub 10 + QV6-va = 10 IT & 10 IT Qur - vai ix VT 10 From equation ☺ we know that then sva + 5x VI - VG 10 = 0.5 VT 3va = VT -0.507 3 a O. BUT equ 3) Substitute in in eq = 10 IT UT [e- 0 3 = 063 = 10 IT QUT Ons Tout 6 60 TOX bor - VT IT = Ruth 10 IT Х VT 6 s = 5.45452 (Rth = 60 3! step Rtb IL ) ORL According to max power Transfer Theorem, To deliver mase power to load (R2). load resistance should be equal to source Source resistance T. Rth = RL = + Vils! b 60 ti th = 0.833254 ILXRL : → Pmon 9.09 Il = Rth IRL 60+ 60 TI Pmar = (0-83325) x 60 3.787_watts power to terminal a&b 11 3.787 watts more transfer