a)
Age(Years) |
Positive for SCD |
likelihood |
Negative for SCD |
likelihood |
<1 |
8 |
0.035 |
17 |
0.075 |
1-2 |
36 |
0.160 |
76 |
0.337 |
3-4 |
16 |
0.071 |
45 |
0.200 |
5-6 |
8 |
0.035 |
19 |
0.084 |
TOTAL |
68 |
0.301 |
157 |
0.696 |
b) by using the law of total likelihood from above tree diagram the prevalence of sickle cell disease(SCD) Iin the 225 children observed in the study
from above table
total likelihood for positive = 0.301
number of childrens = 225
prevalence of sickle cell disease(SCD) = total likelihood for positive x number of childrens
= 0.301 x 225 = 67.725 i.e 68
from tree diagram
the total likelihood for positive = 0.035+0.160+0.071+0.035 = 0.301
number of childrens = 225
prevalence of sickle cell disease(SCD) = total likelihood for positive x number of childrens
= 0.301 x 225 = 67.725 i.e 68
c)
Positive for SCD |
Positive for SCD |
Negative for SCD |
Total |
|
<1 |
watched |
8 |
17 |
25 |
|
anticipated |
7.56 |
17.44 |
25.00 |
(O – E) |
0.44 |
-0.44 |
0.00 |
|
(O – E)^2 / E |
0.03 |
0.01 |
0.04 |
|
% of chisquare |
3.7% |
1.6% |
5.4% |
Positive for SCD |
Positive for SCD |
Negative for SCD |
Total |
|
1-2 |
watched |
36 |
76 |
112 |
|
anticipated |
33.85 |
78.15 |
112.00 |
(O – E) |
2.15 |
-2.15 |
0.00 |
|
(O – E)^2 / E |
0.14 |
0.06 |
0.20 |
|
% of chi square |
19.6% |
8.5% |
28.0% |
Positive for SCD |
Positive for SCD |
Negative for SCD |
Total |
|
3-4 |
watched |
16 |
45 |
61 |
|
anticipated |
18.44 |
42.56 |
61.00 |
(O – E) |
-2.44 |
2.44 |
0.00 |
|
(O – E)^2 / E |
0.32 |
0.14 |
0.46 |
|
% of chi square |
46.0% |
19.9% |
66.0% |
Positive for SCD |
Positive for SCD |
Negative for SCD |
Total |
|
5-6 |
watched |
8 |
19 |
27 |
|
anticipated |
8.16 |
18.84 |
27.00 |
(O – E) |
-0.16 |
0.16 |
0.00 |
|
(O – E)^2 / E |
0.00 |
0.00 |
0.00 |
|
% of chi square |
0.4% |
0.2% |
0.6% |
Positive for SCD |
Positive for SCD |
Negative for SCD |
Total |
|
TOTAL |
watched |
68 |
157 |
225 |
|
anticipated |
68.00 |
18.84 |
27.00 |
(O – E) |
0.00 |
0.00 |
0.00 |
|
(O – E)^2 / E |
0.49 |
0.21 |
0.70 |
|
% of chi square |
69.8% |
30.2% |
100% |
Hence chi-square = 0.70
degrees of freedom = 3
p-esteem = 0.8734
Since the p-esteem > 0.05, it gives the idea that age and predominance of Sickle cell disease are not independent.
Problem 1 [9 points]. Sickle cell disease (SCD) is a classification of disorders that affect red...
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