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Problem 1 [9 points]. Sickle cell disease (SCD) is a classification of disorders that affect red blood cells such that they d

b) (3 points) Use the law of total probability for the tree diagram in part (a) to find the prevalence of sickle cell disease

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Answer #1

a)

Age(Years)

Positive for SCD

likelihood

Negative for SCD

likelihood

<1

8

0.035

17

0.075

1-2

36

0.160

76

0.337

3-4

16

0.071

45

0.200

5-6

8

0.035

19

0.084

TOTAL

68

0.301

157

0.696

TREE 1-2 3-4 5-6 0.075 0.035 0.337 0.160 0.200 0.071 0.084 0.035

b) by using the law of total likelihood from above tree diagram the prevalence of sickle cell disease(SCD) Iin the 225 children observed in the study

from above table

total likelihood for positive = 0.301

number of childrens = 225

prevalence of sickle cell disease(SCD) =  total likelihood for positive x number of childrens

= 0.301 x 225 = 67.725 i.e 68

from tree diagram

the total likelihood for positive = 0.035+0.160+0.071+0.035 = 0.301

number of childrens = 225

prevalence of sickle cell disease(SCD) =  total likelihood for positive x number of childrens

= 0.301 x 225 = 67.725 i.e 68

c)

Positive for SCD

Positive for SCD

Negative for SCD

Total

<1

watched

8

17

25

          

anticipated

7.56

17.44

25.00

(O – E)

0.44

-0.44

0.00

(O – E)^2 / E

0.03

0.01

0.04

% of chisquare

3.7%

1.6%

5.4%

Positive for SCD

Positive for SCD

Negative for SCD

Total

1-2

watched

36

76

112

          

anticipated

33.85

78.15

112.00

(O – E)

2.15

-2.15

0.00

(O – E)^2 / E

0.14

0.06

0.20

% of chi square

19.6%

8.5%

28.0%

Positive for SCD

Positive for SCD

Negative for SCD

Total

3-4

watched

16

45

61

          

anticipated

18.44

42.56

61.00

(O – E)

-2.44

2.44

0.00

(O – E)^2 / E

0.32

0.14

0.46

% of chi square

46.0%

19.9%

66.0%

Positive for SCD

Positive for SCD

Negative for SCD

Total

5-6

watched

8

19

27

          

anticipated

8.16

18.84

27.00

(O – E)

-0.16

0.16

0.00

(O – E)^2 / E

0.00

0.00

0.00

% of chi square

0.4%

0.2%

0.6%

Positive for SCD

Positive for SCD

Negative for SCD

Total

TOTAL

watched

68

157

225

          

anticipated

68.00

18.84

27.00

(O – E)

0.00

0.00

0.00

(O – E)^2 / E

0.49

0.21

0.70

% of chi square

69.8%

30.2%

100%

Hence chi-square = 0.70

degrees of freedom = 3

p-esteem = 0.8734

Since the p-esteem > 0.05, it gives the idea that age and predominance of Sickle cell disease are not independent.

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