Question

Problem 2 (30 pts): Consider the following circuit. Find both the Thévenin and Norton equivalent with respect to terminals a and b. Be sure to label which is which. 400 250 W

Answer 1

o] given 4oor Multa 2sor aux kr 0-02A 120 (5) b - caluculation RhRN short open the the voltage current source source 4oou 2 son s 2000 b Now aud Excite Find ab with 1v source current deliver by 10 source (VOW REG=RN =

loor C 2501 2000, - apply KuL in loop [dotter] 5 -1+2 Vy +250 I + Un=0 o = 3Vx+ 250 I = 1 — also Eron Circuit I= ve o tuo oro (ty KCl at c] I = 3x163 Vg = V2 = 333.333 I put na in = 3(333. 333 1] +250 I = 1 1000 I +250 I = || 1250 I = 1 I= 8x104 : Rih=RN = 8XLTY Rih= RN=1250m

caluculation :- u Sa X Loor M - 250 ~ 2VT 0.02 A i con Vy & 120g 1 - 2 V3 + apply KCL in dotter loop - VX + 250(1) -2 Va + Vth = 0 SI = 0 = Uth = 3 VA = 3 VE Now apply Noda analysis at ux Node (c] x Vx No Nodal analy Now va-12 Va - 0102 =0 2000 400 ri + 12 z va ] - + 0102 +002 400 LDO 2006 3x103 Ux=0.05 Va = 16.667 Vin= 3x16.667 luth = 50 voit 1

(Bio) IN caluculation w ! 250 2 212 4oor 5 X Y 2000 r 209 120 @ IN apply kul in sotty loop = -VX+250 IN - 2V2 =0 = 250 IN = 3 V7 - apply modal analysis at ve Sa Lene Ux-(-2val=0 -0.02 400 12 0-02 L06 2000 vo (2.) =0-02 -02 LO

va (...] = 200 3 x 16 3 2 so 250 In= = In=1245 = 0.04 Amp 7 The niniuant circuit is 12901 ^ 500 h . b (ii) norton's circuit is 0.04 AU 31250r