Question

Part A What is the boiling point of water at an elevation of 1.25*10* ft ? Express your answer with the appropriate units using three significant figures View Available Hint(s) CHAR O ? T= Value Submit Provide Feedback

Answer 1

Solution:

Boiling point of water = 100 °C at 760 mm Hg pressure.

>> The decrease in pressure is 19.8 mm Hg for 1000 ft of elevation.

Thus, for 1.25 x 10^4 ft = 12500 ft, the decrease in pressure will be = 19.8 mm Hg x (12500 ft / 1000 ft) = 247.5 mm Hg

Thus,  

The decrease in the boiling point of water

= 0.05 °C x 247.5 mm Hg = 12.4 °C

Hence,

Boiling point of water = 100 °C - 12.4 °C = 87.6 °C