(please round the numbers to the required number of decimal
places.)
What can be said about the p-value? 0.010 < p-value <
0.050.
State the conclusion? 2nd option is correct.
What should we do next to compare the individual means? 4th
option is correct.
s samples of each of our types of cereal grain grown in a certain region were...
Six samples of each of four types of cereal grain grown in a certain region were analyzed to determine thiamin content, resulting in the following data (wg/g): Note: If you want to use this data has been set up so you may copy it directly into R. Wheat=c( 5.3, 4.5, 6.0, 6.2, 6.8, 5.8) Barley=c( 6.5, 7.9, 6.2, 7.6, 5.9, 5.6) Maize=c( 5.8, 4.8, 6.4, 4.8, 6.0, 5.1) Oats = [ 8.2, 6.0, 7.7, 7.0, 5.4, 7.2) In this example...
Six samples of each of four types of cereal grain grown in a certain region were analyzed to determine thiamin content, resulting in the following data (µg/g): Wheat Barley Maize Oats 5.2 6.5 5.8 8.3 4.5 8 4.7 6.1 6 6.1 6.4 7.8 6.1 7.5 4.9 7 6.7 5.9 6 5.5 5.8 5.6 5.2 7.2 a. Does this data suggest that at least two of the grains differ with respect to the true average thiamin content? Use a level α=.05...
1. In an experiment to compare the tensile strengths of 1 - 6 different types of copper wire, ) = 5 samples of each type were used. The between-samples and within samples estimates of a were computed as MSTR = 2649.3 and MSE - 1169.2, respectively. Use the F test at level 0.05 to test Ho: H1 12 - ... - versus Ha: at least two wi's are unequal Calculate the test statistic (Round your answer to two decimal places.)...
2,-/12 pointsDevoreSta19 10.Е.027 Although tea is the world's most widely consumed beverage after water, little is known about its nutritional value. Folacin is the only B vitamin present in any significant amount in tea, and recent advances in assay methods have made accurate determination of folacin content feasible. Consider the accompanying data on folacin content for randomly selected specimens of the four leading brands of green tea. 1: 7.8 6.3 6.6 8.7 9.0 10.1 9.6 2: 5.8 7.5 9.8 6.2...
Consider the following summary data on the modulus of elasticity ( 106 psi) for lumber of three different grades. Grade J Xi. Si 1 11 1.62 0.23 11 1.61 0.22 11 1.54 0.25 Use this data and a significance level of 0.01 to test the null hypothesis of no difference in mean modulus of elasticity for the three grades. Calculate the test statistic. (Round your answer to two decimal places.) f= What can be said about the p-value for the...
An article describes an experiment in which several types of boxes were compared with respect to compression strength (lb). The table below presents the results of a single-factor ANOVA experiment involving I = 4 types of boxes. Type of Box Sample Mean Sample SD 1 Compression Strength (lb) 655.5 788.3 734.3 721.4 679.1 699.4 789.2 772.5 786.9 686.1 732.1 774.8 713.00 46.55 2 756.93 40.34 3 737.1 639.0 696.3 671.7717.2 727.1 698.07 37.20 4 535.1 628.7 542.4 559.0 586.9 520.0...
An article describes an experiment in which several types of boxes were compared with respect to compression strength (lb). The table below presents the results of a single-factor ANOVA experiment involving I = 4 types of boxes. Type of Box Sample Mean Sample SD 713.00 46.55 Compression Strength (lb) 655.5 788.3 734.3 721.4 679.1 699.4 789.2 772:5 786.9 686.1 732.1 774.8 737.1 639.0 696.3 671.7 717.2 727.1 2 756.93 40.34 3 698.07 37.20 4 535.1 628.7 542.4 559.0 586.9 520.0...
An experiment was carried out to investigate the effect of species (factor A, with I = 4) and grade (factor B, with ) = 3) on breaking strength of wood specimens. One observation was made for each species-grade combination-resulting in SSA = 444.0, SSB = 423.6, and SSE = 127.4. Assume that an additive model is appropriate. (a) Test Ho: a = a 2 = az = Q 4 = 0 (no differences in true average strength due to species)...
1 Consider the following summary data on the modulus of elasticity ( 105 psi) for lumber of three different grades. Grades 1.64 0.21 2 1.54 0.23 3 71.42 0.22 Use this data and a significance level of 0.01 to test the null hypothesis of no difference in mean modulus of elasticity for the three grades. Calculate the test statistic. (Round your answer to two decimal places.) What can be said about the P-value for the test? OP-value > 0.100 0.050...
Consider the accompanying data on plant growth after the application of different types of growth hormone. 1: 13 17 8 15 2: 21 12 20 17 3: 19 14 20 17 4: 8 11 18 9 5: 6 12 14 7 (a) Perform an F test at level α = 0.05. State the appropriate hypotheses. H0: μ1 = μ2 = μ3 = μ4 = μ5 Ha: all five μi's are unequal H0: μ1 = μ2 = μ3 = μ4 =...