b)
Applying one way ANOVA:
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 19810.8046 | 3 | 6603.6015 | 3.9030 | 0.0240 | 3.0984 |
Within Groups | 33838.9750 | 20 | 1691.9488 | |||
Total | 53649.7796 | 23 |
f =3.90
c)
0.01 < p value <0.05
An article describes an experiment in which several types of boxes were compared with respect to...
An article describes an experiment in which several types of boxes were compared with respect to compression strength (lb). The table below presents the results of a single-factor ANOVA experiment involving I = 4 types of boxes. Type of Box Sample Mean Sample SD 713.00 46.55 Compression Strength (lb) 655.5 788.3 734.3 721.4 679.1 699.4 789.2 772:5 786.9 686.1 732.1 774.8 737.1 639.0 696.3 671.7 717.2 727.1 2 756.93 40.34 3 698.07 37.20 4 535.1 628.7 542.4 559.0 586.9 520.0...
An article describes an experiment in which several types of boxes were compared with respect to compression strength (lb). The table below presents the results of a single-factor ANOVA experiment involving I = 4 types of boxes. Type of Box Compression Strength (lb) Sample Mean Sample SD 1 655.5 788.3 734.3 721.4 679.1 699.4 713.00 46.55 2 789.2 772.5 786.9 686.1 732.1 774.8 756.93 40.34 3 737.1 639.0 696.3 671.7 717.2 727.1 698.07 37.20 4 535.1 628.7 542.4 559.0 586.9...
1 An article describes an experiment in which several types of boxes were compared with respect to compression strength (lb). The table below presents the results of a single-factor ANOVA experiment involving I = 4 types of boxes. Type of Box Compression Strength (lb) Sample Mean Sample SD 655.5 788.3 734.3 721.4 679.1 699.4 713.00 46.55 789.2 772.5 786.9 686.1 732.1 774.8 756.93 40.34 3 737.1 639.0 696.3 671.7 717.2 727.1 698.07 37.20 4 535.1 628.7 542.4 559.0 586.9 520.0...
The following data refers to yield of tomatoes (kg/plot) for four different levels of salinity. Salinity level here refers to electrical conductivity (EC), where the chosen levels were EC = 1.6, 3.8, 6.0, and 10.2 nmhos/cm. (Use i = 1, 2, 3, and 4 respectively.) 1.6: 59.7 53.5 56.2 63.7 58.8 3.8: 55.9 59.1 52.3 54.2 6.0: 51.3 48.8 53.6 48.5 10.2: 44.6 48.9 41.0 47.1 46.8 Use the F test at level a = 0.05 to test for any...
=========================================== f=25.09 is wrong. Olestra is a fat substitute approved by the FDA for use in snack foods. Because there have been anecdotal reports of gastrointestinal problems associated with olestra consumption, a randomized, double-blind, placebo-controlled experiment was carried out to compare olestra potato chips to regular potato chips with respect to GI symptoms. Among 500 individuals in the TG control group, 16.6% experienced an adverse GI event, whereas among the 500 individuals in the olestra treatment group, 14.8% experienced such...
1. In an experiment to compare the tensile strengths of 1 - 6 different types of copper wire, ) = 5 samples of each type were used. The between-samples and within samples estimates of a were computed as MSTR = 2649.3 and MSE - 1169.2, respectively. Use the F test at level 0.05 to test Ho: H1 12 - ... - versus Ha: at least two wi's are unequal Calculate the test statistic (Round your answer to two decimal places.)...
2. [-/10 Points] DETAILS DEVORESTAT9 10.E.003. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER The lumen output was determined for each of I = 3 different brands of lightbulbs having the same wattage, with J = 7 bulbs of each brand tested. The sums of squares were computed as SSE = 4776.4 and SST = 598.4. State the hypotheses of interest (including word definitions of parameters). u; = sample average lumen output for brand i bulbs Ho: M1 = ll2 =...
An experiment was carried out to investigate the effect of species (factor A, with I = 4) and grade (factor B, with ) = 3) on breaking strength of wood specimens. One observation was made for each species-grade combination-resulting in SSA = 444.0, SSB = 423.6, and SSE = 127.4. Assume that an additive model is appropriate. (a) Test Ho: a = a 2 = az = Q 4 = 0 (no differences in true average strength due to species)...
An experiment was carried out to investigate the effect of species (factor A, with I = 4) and grade (factor B, with ) = 3) on breaking strength of wood specimens. One observation was made for each species-grade combination-resulting in SSA = 443.0, SSB = 428.6, and SSE = 122.4. Assume that an additive model is appropriate. (a) Test Ho: a1 = a2 = 03 = 24 = 0 (no differences in true average strength due to species) versus Ha:...
In an experiment to compare the tensile strengths of I = 6 different types of copper wire, J = 5 samples of each type were used. The between-samples and within-samples estimates of σ2 were computed as MSTr = 2678.3 and MSE = 1188.2, respectively. Use the F test at level 0.05 to test H0: μ1 = μ2 = . . . = μ6 versus Ha: at least two μi's are unequal. 1. Calculate the test statistic. (Round your answer to...