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9. In Z/31Z, using Proposition 3, find a primitive root modulo 31.Proposition 3. Let a,b be elements of a finite abelian group. If a has order r, and b has order s, and (r, s) = 1, then ab ha

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Note that 25 = 1 (mod 31) 2 is not primitive not of 31 let ustry 3 next. So that 35 = 330 3² 9 (modat) and 3 = 27 ned 31) we

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9. In Z/31Z, using Proposition 3, find a primitive root modulo 31. Proposition 3. Let a,b...
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