Question

This is one of my lab reports, I am curious if I have done it right? Can anyone help?

Data And Lab Report Submission - Hydration Of 1-Hexene

Hydration of 1-Hexene

Data Collection

Amount of reactant used in grams

0.694

Product obtained in grams

0.785

(24pts) Calculations

Use the mass of reactant and product recorded above to complete the following calculations.

(4pts)

Amount of reactant in moles

(4pts)

Product obtained in moles

(6pts)

Product theoretical yield (g)

(6pts)

Product percent yield (%)

(4pts)

Write the equation for the reaction

(25pts) Post Lab Questions

(8pts)

1. Is your percent yield within reason of what you would expect? Explain your answer.

(8pts)

2. How can the IR spectrum be used to show that there is not starting material left and the products are alcohols?

(9pts)

3. Can the IR spectrum be used to determine a mixture of 2-hexanol and 1-hexanol? Explain your answer.

Answer 1

Hydeation of 1- Hexene: v & ho + Ho - H+ WA - Hexene OH 2-Hexandr (major product) moles of 1- Hexene: 2 ind 1-Hexene 0.694 9 l-levene x md =1000836 l-lexere 8 39 1-Hexene moes go 1- Hexene = 0.00 836 mol moles of 2-iderand ind 2-Hexand 0-7859 2-Idexand X 0.00769.00 10292-1depany 2-Hexory moles gi 2-1Hexaned = 10.00769 mol Product Theoretical yield: x 0.6949.1-Hexene' x in de lilfexera xind 2-Hexand 8391 Hexene Inde Irlfexene 0 vớp 83 6 4 2-Je van x 2022 9 2-4cean II In de 2-Hexand -10-8539 2-iderand =10-853

Prodat percent yield.. %yield = actual yield X160 Theoretical yield 0.7859 X 100 0.8539 92%. Equation Ht W + H2O OH 2-Hexene 2- Hexanol magor product From the percent yield (1927), more bield of Product obtained