Question

a 25 ksi a. Draw Mohr's circle for this state of stress b. Determine the normal and shear stresses acting on the indicated cutting plane and show these stresses in a sketch (following the format we use in class).

Answer 1

solution Ary=25ksi E n loksi = txy /.600 Hp 82=0 So. Center of mohr circle (7,0) = (0279 ,0) = ( 0+25",0) = (12:500) ksi Radius of mohrcircle R= () #cry-10-23)+102 = 16 ksi Mohr's circle for above state stress - 9). Gy, łty) R. H D B, EG(+) (G, Txy) - (+) Txy angle of rotation of plane from ventical plane is 8= -60° (clockwise? :: a = tawi (et) a to i ne) =3866 5-60

Since, 20 = –2x60 = -120° so B = 12e-05 120°– 38.66*= 81.34" b) Normal stress on indicated plane Das One EJ- R.Comm= 19.5 – 16x cos( 81.390) 32'On = 10.09|3i las' toy= 6+12.25-60.09=14.3 85i & shear stress on indicated plane I's -Rico sin 3 = -16.sin(21-390) t=-15,82 ksi A Y = 95320 Txy=loksi Tzu By=18.91681. 18.9169;X ' It ly'= Ts-15182 ksi H on=loogksia Ssi
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