ers Ux Use this to answer questions 11-12. Ina random sample of 1000 college freshmen, 37%...
Wel A college admissions officer takes a simple random sample of 110 entering freshmen and computes their mean mathematics SAT score to be 465. Assume the population standard deviation is 0 - 92. Construct a 90% confidence interval for the mean mathematics SAT score for the entering freshmen class (373.557 (451, 479) (463,467)
A random sample of ?=80n=80 in-coming college freshmen showed that 44 were planning to bring a car with them to campus next fall. Suppose that we are interested in forming a confidence interval at 90 percent for the proportion of all in-coming college freshmen who are planning to bring a car to campus next fall. Where appropriate, express your answer as a proportion (not a percentage). Round answers to three decimal places. (a) The estimate is: . (b) The standard error...
Problem 3. (17 points A random sample of 80 in-coming college freshmen showed that were planning to bring a car with them to campus next fail. Suppose that we are interested informing a confidence interval at 90 percent for the proportion of all incoming college freshmen who are planning to bring a car to campus next fall Where appropriate, express your wer a proportion not a percentage. Round answers to three decimal places The estimates The standard errors The mutipli...
Problem 4. (17 points) A random sample of n = 80 in-coming college freshmen showed that 28 were planning to bring a car with them to campus next fall. Suppose that we are interested in forming a confidence interval at 99.7 percent for the proportion of all in-coming college freshmen who are planning to bring a car to campus next fall. Where appropriate, express your answer as a proportion (not a percentage). Round answers to three decimal places. (a) The...
1. A popular claim, nicknamed "feshman fifteen," states that many college students gain weight point) in their freshman year. You are given the 95% confidence interval as 559% <P < 78 4% Correctly interpret the interval. There is a 95% chance tha the true percentage of college freshmen who gain weight is between 559% and 78 496. 95% of sample college freshmen who gain weight will fall between 55.9% and 78 4% We are confident that 95% of college freshmen,who...
Sleeping outlier: A simple random sample of eight college freshmen were asked how many hours of sleep they typically got per night. The results were 24 6 8.5 8 8.5 7.5 6.5 9 Send data to Excel Notice that one joker said that he sleeps 24 a day. Part: 0/ 3 Part 1 of 3 (a) The data contain an outlier that is clearly a mistake. Eliminate the outlier, then construct a 90 % confidence interval for the mean amount...
Assume an approximate normal distrihution. IS. A random sample of 12 eniployees of the Wlergate Carpet Company wed an average contribution of $8.00 to the American Cancer Socicty, with a landard deviation of $1.25, Construct u 90% wnfidence interva: for the average contribution by all employces of the Watergate Carpet Company to the American Cancer Society. Assume the contribuions to hc?pproxi- matcly normally distributed. Suction 8.5 16. (a) A random sample of 200 voters from Salem, Virginia, is selected and...
A statistics student at a New York State community college, randomly samples 900 students who own cell phones to determine if they play games on their phones. 75% stated that they use their mobile phones to play games. Using this information, then: construct a 90% confidence interval (to 4 decimal places) for the population proportion, p, of NYS community college cell phone users who play games on their phones. construct a 99% confidence interval (to 4 decimal places) for the...
A random sample of community college students was asked the number of hours they sleep on a typical week-night during a given academic term. The sample data are as follows: 8 6 4 5 3 7 S 4 3 4 4 5 6 8 7 7 7 3 3 4 What is the 90% confidence interval estimate for the true mean amount of sleep time per night spent by community college students during a academic term? a) The data give...
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Round to three decimal places. Of 89 adults selected randomly from one town, 66 have health insurance. Find a 90% confidence interval for the true proportion of all adults in the town who have health insurance.