What is ∆Grxn at 25ºC for the following reaction: 4Au3+(aq,
0.050 M) + 12OH–(aq, 0.0020 M) --> 4Au(s) + 3O2(g, 0.15 atm) +
6H2O(l)? Given the following standard reduction potentials:
Au3+(aq) + 3e– --> Au(s); Eº = 1.40 V O2(g) + 2H2O(l) + 4e–
--> 4OH–(aq); Eº = 0.401 V
What is ∆Grxn at 25ºC for the following reaction: 4Au3+(aq, 0.050 M) + 12OH–(aq, 0.0020 M)...
Standard Electrode Potentials at 25?C Reduction Half-Reaction E?(V) F2(g)+2e? ?2F?(aq) 2.87 Au3+(aq)+3e? ?Au(s) 1.50 Cl2(g)+2e? ?2Cl?(aq) 1.36 O2(g)+4H+(aq)+4e? ?2H2O(l) 1.23 Br2(l)+2e? ?2Br?(aq) 1.09 NO3?(aq)+4H+(aq)+3e? ?NO(g)+2H2O(l) 0.96 Ag+(aq)+e? ?Ag(s) 0.80 I2(s)+2e? ?2I?(aq) 0.54 Cu2+(aq)+2e? ?Cu(s) 0.16 2H+(aq)+2e? ?H2(g) 0 Cr3+(aq)+3e? ?Cr(s) -0.73 2H2O(l)+2e? ?H2(g)+2OH?(aq) -0.83 Mn2+(aq)+2e? ?Mn(s) -1.18 How can the table be used to predict whether or not a metal will dissolve in HCl? In HNO3? Drag the terms on the left to the appropriate blanks on the right to...
Please show all steps taken (prefer typed solution)
Half-Reaction
E
°
(V)
Ag+ (aq) + e− → Ag (s)
0.7996
Al3+ (aq) + 3e− → Al (s)
−1.676
Au+ (aq) + e− → Au (s)
1.692
Au3+ (aq) + 3e− → Au (s)
1.498
Ba2+ (aq) + 2e− → Ba (s)
−2.912
Br2 (l) + 2e− → 2Br− (aq)
1.066
Ca2+ (aq) + 2e− → Ca (s)
−2.868
Cl2 (g) + 2e− → 2Cl− (aq)
1.35827
Co2+ (aq) + 2e−...
Decide whether or not each metal dissolves in 1 molL−1HIO3(aq). Standard Electrode Potentials at 25 ∘C Reduction Half-Reaction E∘(V) IO3−(aq)+6H+(aq)+5e− →12I2(aq)+3H2O(l) 1.20 Au3+(aq)+3e− →Au(s) 1.50 Cr3+(aq)+3e− →Cr(s) -0.73 Part A Au dissolves does not dissolve Cr dissolves does not dissolve
1. Consider the reaction below: 3Ag2S(s) + 8H+(aq) + 2NO3-(aq) ? 6Ag+(aq) + 3S(s) + 2NO(g) + 4H2O(l) In this reaction, which species is reduced? 2. Calculate Ecell for the following electrochemical cell which is operating under nonstandard conditions: Cr | Cr3+(0.010 M) || Ag+(0.00010 M) | Ag The relevant standard reduction potentials are: Cr3+(aq) + 3e- ? Cr(s) Eº = ?0.74 V Ag+(aq) + e- ? Ag(s) Eº = +0.80 V
Calculate the cell potential for the galvanic cell in which the reaction Fe(s)+Au3+(aq)−⇀↽− Fe3+(aq)+Au(s) occurs at 25 ∘C , given that [Fe3+]=0.00150 M and [Au3+]=0.795 M . Refer to the table of standard reduction potentials. E= V
Calculate the cell potential for the following reaction as written at 25.00 °C, given that [Mg2 ] = 0.774 M and [Sn2 ] = 0.0190 M. Standard reduction potentials can be found here. Reduction Half-Reaction Standard Potential Ered° (V) F2(g) + 2e– → 2F–(aq) +2.87 O3(g) + 2H3O+(aq) + 2e– → O2(g) + 3H2O(l) +2.076 Co3+(aq) + e– → Co2+(aq) +1.92 H2O2(aq) + 2H3O+(aq) + 2e– → 2H2O(l) +1.776 N2O(g) + 2H3O+(aq) + 2e– → N2(g) + 3H2O(l) +1.766 Ce4+(aq) + e– → Ce3+(aq)...
E° = -0.04 V For the reaction: Au(s) + 4H+ (aq) + NO3(aq) + 4Cl(aq) → AuCl4- (aq) + NO(g) + 2H20 If the standard potential for the reduction of NO3(aq) to NO(g) is +0.96 V, determine the value of Eº for the following half-reaction AuCl4 (aq) + 3e → Au(s) + 4C1 (aq)
A) Use tabulated electrode potentials to calculate ΔG∘ for the reaction. 2K(s)+2H2O(l)→H2(g)+2OH−(aq)+2K+(aq) B) (Refer to the following standard reduction half-cell potentials at 25∘C: VO2+(aq)+Ni2+(aq)2H+(aq)++2e−e−→ →Ni(s)VO2+(aq) +H2O(l)E∘=−0.23V E∘=0.99V) An electrochemical cell is based on these two half-reactions: Oxidation:Reduction:Ni(s)VO2+(aq,0.024M)+2H+(aq,1.4M)+e−→→Ni2+(aq,1.8M)+2e−VO2+(aq,1.8M)+H2O(l) Calculate the cell potential under these nonstandard concentrations. C) Standard reduction half-cell potentials at 25∘C Half-reaction E∘ (V ) Half-reaction E∘ (V ) Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) − 0.45 Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) − 0.50 Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) − 0.73 Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) − 0.76...
Given the following standard reduction potentials Ru2+(aq) + 2e– → Ru(s) Eº = 0.46 V Pb2+(aq) + 2e– → Pb(s) Eº = –0.13 V Fe2+(aq) + 2e– → Fe(s) Eº = –0.44 V Cr3+(aq) + 3e– → Cr(s) Eº = –0.74 V Mn2+(aq) + 2e– → Mn(s) Eº = –1.19 V Mg2+(aq) + 2e– → Mg(s) Eº = –2.36 V choose all metals that will not prevent corrosion of iron by cathodic protection. Group of answer choices only Pb only...
e. Determine Kc for this reaction. If your calculator gives an 'overflow error', state this fact. f. Water samples with trace amounts of dissolved Au3+ were used as the aqueous solution in the Au/Au3+ half-cell in the above battery and the following voltages were obtained. Finish the table by determining the concentration of Au(aq) is these samples. Show your work clearly on the back of this page. [Au”](M) Measured voltage 2.10 1.98 1.95 1.90 117 1) High quality Au/Au and...