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Hess's Law Review Questions Name Section 1. Write a balanced equation for the formation of CO2,...
Honors Chemistry Name Period Date Thermochemical Equations and Hess's Law Directions: Answer the following questions in the space provided. 1. The combustion of ethylene, CHs is (a) Is this reaction endothermic or exothermic? (b) Calculate the AH when 12.44 grams of ethylene react with excess oxygen gas. 2. The value of AH for the reaction below is-790.0 k. 25 (s) + 302 (8) 2503(8) (a) Calculate the AH when 1.78 x 10 grams of sulfur react with excess oxygen gas....
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
a) Use Hess's law to calculate the enthalpy change for the reaction: 3C(s) + 4H2(g) + ½O2(g) → C3H8O(l) Given the following thermochemical equations: 2C3H8O(l) + 9O2(g) → 6CO2(g) + 8H2O(l) ΔH = -4042.6 kJ/mol C(s) + O2(g) → CO2(g) ΔH = -393.51 kJ/mol H2(g) + ½O2(g) → H2O(l) ΔH = -285.83 kJ/mol (in kJ/mol) A: -267.7 B: -302.6 C: -341.9 D: -386.3 E: -436.5 F: -493.3 G: -557.4 H: -629.9 b) Define if the following statement is an endothermic process or exothermic...
PROBLEM-SOLVING CLASS ACTIVITY 11 Use Hess's Law to calculate the enthalpy of formation of CH2OH: C(graphite) + 2 H2(g) + 1026) → CH2OH(1) Given the following data: CH2OH() • 02(9) + CO2(g) + 2H2O(1) AH°: -726.4 kJ/mol C(graphite). O2(g) → CO2(9) AH' = -393.5 kJ/mol H2(g) + 40269) → H2O(1) AH = -285.8 kJ/mol
Ho ilacer e trunschpl Use Hess's Law to calculate the standard enthalpy (AHº) for the foll standard enthalpy (AH) for the following reaction inolonce to the on an C(s) + O2(g) → CO(g) given the following two equations. C(s) +502(9) – co(9) AH° = -110.5 kJ CO2(g) – CO(g) +502(9) AH° = +283.0 kJ [15]
Using Hess's Law, determine the enthalpy change of the following reaction. CS2(1) + 3 O2(g) --> CO2(g) + 2 SO2(g) C(s) + O2(g) --> CO2(g) AH = -393.5 kJ/mol S(s) + O2(g) --> SO2(g) AH = -296.8 kJ/mol C(s) + 25(s) --> CS2(8) AH = +87.9 kJ/mol -899.2 kJ O-778.2 kJ -602.4 kJ - 1075.0 kJ
THERM OCHEMISTRY I1: HESS'S LAW OF CONSTANT HEAT SUMMATION ADVANCED PROBLEM ASSIGNMENT Dare Section Name READ THE EXPERIMENTAL DISCUSSION FIRST SHOW CALCULATION SET-UPI SIGNS! SIGNIFICANT FIGUREESi The 1.00 M solutions of HNO, and NaOH used in this experiment are prepared by diluting 6.00 M stock solutions. 1 What volume of 6.00 M stock solurion and whar volume of water is required to prepare 50.0 mL of 1.0 M solution? mL H.O mL 6.00 M Stock Solution How many moles of...
Prelab questions 1. What is the significance of the statement "qsystem + Surroundings zero Law of Thermodynamics"? statement "qsystem + Surroundings = zero" in relation to the First 2. A student measured heat of neutralization in a Styrofoam "Coffee Cup calorimeter by mixing 25.0 mL of 1.0 M NaOH solution with 250 mL of 10 M HCI solution. Write the balanced equation and identify the limiting reactant in this experiment. If heat of this exothermic reaction was determined to be...
1. Enthalpy changes for an endothermic reaction are given a negative sign. 2. According to Hess's Law, if the coefficients of a chemical equation are altered by multiplying or dividing by a constant factor, then the cH is altered the same way. 3. The overall order of reaction is the product of the individual orders of reaction for each reaction. 4. An ineffective collision is one that has sufficient energy and correct orientation so that the reaction can proceed. 5....