6) The rate constant for the first-order decomposition of N2O5 in the reaction 2N2O5(g) → 4NO2(g) + O2(g) is k=3.38 x 10-5 s-1 at 25°C. What is the half-life of N2O5? What will be the total pressure, initially 88.3 kPa for the pure N2O5 vapour, (a) 10 s, (b) 10 minutes after initiation of the reaction?
6) The rate constant for the first-order decomposition of N2O5 in the reaction 2N2O5(g) → 4NO2(g)...
7) The rate constant for the reaction 2N2O5(g) 25°C 4NO2(g) +O2(g) is k = 3.38x10-5/s at a) Enter the half-life of N20s in seconds. Use two significant figures and do not enter units b) Enter the total pressure in kPa 10 seconds after initiation of the reaction if initially there was 88.3kPa of pure N2O5 vapor. Use two significant figures and do not enter the units c) Enter the total pressure in kPa 10 minutes after initiation of the reaction...
The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.30×10−2 mol of N2O5(g) in a volume of 1.5 L . a. How many moles of N2O5 will remain after 6 min ? b. How many minutes will it take for the quantity of N2O5 to drop to 1.9×10−2 mol ? c. What is the half-life of N2O5 at 70∘C?
The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.00×10−2 mol of N2O5(g) in a volume of 2.0 L . How many moles of N2O5 will remain after 7.0 min? How many minutes will it take for the quantity of N2O5 to drop to 1.6×10−2 mol? What is the half-life of N2O5 at 70∘C?
The decomposition of N2O5 is described by the following equation. 2N2O5(g) → 4NO2(g) + O2(g) If the rate constant is 2.50 × 10−4 s−1, what is the half-life of this reaction?
The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.60×10−2 mol of N2O5(g) in a volume of 2.3 L Part A How many moles of N2O5 will remain after 4.0 min ? Part B How many minutes will it take for the quantity of N2O5 to drop to 1.8×10−2 mol ? Part C What is the half-life of N2O5 at 70∘C?
The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.50×10−2 mol of N2O5(g) in a volume of 1.8 L . Part A: How many moles of N2O5 will remain after 4.0 min ? Part B: How many minutes will it take for the quantity of N2O5 to drop to 1.9×10−2 mol ? Part C: What is the half-life of N2O5 at 70∘C?
The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.40×10−2 mol of N2O5(g) in a volume of 2.1 L. a) How many moles of N2O5 will remain after 7.0 min? b) How many minutes will it take for the quantity of N2O5 to drop to 1.6×10−2 mol?
The decomposition of N2O5 18.3 2N2O5 4NO2+O2 is studied by measuring the concentration of oxygen as a func- tion of time, and it is found that OlP dt (1.5 x 10sN2O5] = at constant temperature and pressure. Under these conditions the reaction goes to completion to the right. What is the half- life of the reaction under these conditions?
The decomposition of N2O5 in solution in carbon tetrachloride proceeds via the reaction: 2N2O5 (soln) → 4NO2 (soln) + O2 (soln) The reaction is first order and has a rate constant of 4.82 x 10-3 s-1 at 64 oC. The reaction is initiated with 0.058 mol in a 1.25 L vessel. What is the half-life of the reaction?
The decomposition of N2O5 in carbon tetrachloride proceeds as follows: 2N2O5→4NO2+O2 The rate law is first order in N2O5. At 64*C the rate constant is 4.82 ×10^−3s^−1 The rate law is 4.82x10-3s-1 [N2O5] The rate of rxn when [N2O5]=2.40x10^-2 M is 1.16x10^-4 M/s What happens to the rate when the concentration of N2O5 is doubled? What about halved? The answers are NOT 9.64x10^-3 and 2.41x10^-3 M/s