You add 19.00 mL of 0.600 M NaOH to 50.00 mL of pure water, and to...

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Answer 1

Answer #1

No. of moles of NaOH = 0.600 moe x 18.00ml x 0.001L ImL = 1.14 x10h mor No. of males of Hel = 0.400 moe x 3.00 mL x 0.001L Im

Answer 2

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