You add 9.00 mL of 0.200 M NaOH to 50.00 mL of pure water, and to...

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You add 9.00 mL of 0.200 M NaOH to 50.00 mL of pure water, and to this mixture you then add 12.00 mL of 0.600 M HCI. What wil

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Answer 1

Answer #1

first step is dilution of NaOH then in second step the titration occurs with HCl. we have to deduce finally how much is the concentration left for H+ or OH- then we will be able to tell what is the Ph

see image below oiuition of NOOH mv - Mg V₂m,-0.200 v-9 me m₂ = 2. = 9+50 V = 59 Total you 10.200x9 = m2 859 M₂ -0.0305 New NaOH concentratio HU Ht te TH I will be same as he Oo76 Гра - Top Ги*] на | 18 | - Lo9 Гоо 167

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Answer 2

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