You add 1.00 mL of 0.300 M NaOH to 50.00 mL of pure water, and to...

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You add 1.00 mL of 0.300 M NaOH to 50.00 mL of pure water, and to this mixture you then add 16.00 mL of 0.800 M HCI. What wil

You add 16.00 mL of 0.600 M NaOH to 50.00 mL of pure water, and to this mixture you then add 100 mL of 0.300 M HCL What will

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Answer 1

Answer #1

Number of moles of NaOH = 0.600 mol/Lx 16x10 L = 9.6x10-3 mol Number of moles of HCl = 0.300 mol/L x 1 x 10 L = 3x10-4 mol Nu Total volume of the solution = (16+50+1) mL = 67 mL The concentration of OH-ions - 9.3x10-3 mol 67 x 10-3 L = 0.138 M pott =

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