You add 7.50 ml of 0.220 M NaOH to 50.00 mL of pure water, and to this mixture you then add 12.50 ml of 0.150 HCI....

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Answer 1

Answer #1

1mL 1 mc _3 - NaOH + HU → nac + H₂O No. of moles of NaOH = 0.220 mar x 7.50 mL x 0.001L = 1.65 x 103 mol No.of males of Hel =

Answer 2

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