Ka = 1.8*10^-5
pKa = - log (Ka)
= - log(1.8*10^-5)
= 4.745
use:
pH = pKa + log {[conjugate base]/[acid]}
= 4.745+ log {0.39/0.15}
= 5.16
Answer: 5.16
Determine the pH of a 0.15 Macetic acid/0.39 M sodium acetate solution where K3=1.8 x 10-5...