Question

meed help with part c and e

[References) How would you prepare 1.10 L of a 0.50-M solution of each of the following? . a. H2SO4 from "concentrated" (18 M) sulfuric acid Dilute 30.55 mL of concentrated H2SO4 to a total volume of 110 L with wa b. HCl from "concentrated" (12 M) reagent O EO 9 21 Dilute 45.83 mL of concentrated HCl to a total volume c. NiCl, from the salt NiCl2 - 6H2O Dissolve g NiCl, 6H2O in water, and add water until the total volume of the solution is 110L d. HNO3 from “concentrated” (16 M) nitric acid Dilute 34.37 mL of concentrated HNO3 to a total volume of 110 L with water e. Sodium carbonate from the pure solid Dissolve gNa, CO, in water, and add water until the total volume of the solution is 110 L O 39 Submit Answer Try Another Version 4 item attempts remaining

Answer 1

C. Relative molar mass of NiCl2 .6H2O = 58.69+35.45*2+6*(16+2*1.008) = 237.64 gm/mol

Mass required for 1lt of 0.50M solution = 0.5*237.64= 118.82gm

so mass required for 1.10 L of 0.50M =118.82*1.10 gm = 130.702gm

E. Molar mass of Na2CO3 = 105.99 gm/mol

0.50M*1.10L= 0.55 mol

no of moles needed= 105.99*0.55= 58.30 gm