Question

What volume of CO2(g) at 25°C and 760 Torr is produced when 1.00 kg of calcium carbonate is used to neutralize a sulfuric acid spill? The equation for the reaction is CaCO3(s) + H2SO4(aq) ® CaSO4(s) + CO2(g) + H2O(l) A. 321 L B. 122 L C. 488 L D. 22.4 L E. 244 L Show steps please.

Answer 1

So use farcela Pelle = 2 / to breg conde * STP * Corso ? zlatom - Lahm (geen in Q.) 224x298= 273 x = 24-455L e react with the rade of co₂ 3 b brodere → -> 24.452 27 co_ ct 298k & schem le looga Cacer 39 43 1009 leses a Goog > 2414 . pn 1000 = 244.5 Lf coa , te behaal) = 244h is correct ore

Civen :- To fund:- T= 25°C ie 298k P = 760 forie dam co volume = ?? loog of CaCO₃ Solution :- We know, Given Calo (s) & th 80g Coa) Cason(s) + 40 (1) +ąg Slep I - Balance the equation, if not balanced. As it - already balanced So, no change f or skap I - fud Molar was Glog & Vol of Co, at STP- ® M. mars og COA! асо, = M-молл 0 % + мало ) с (3х М. Каль 20) = 40 + 12 + (1643) = 40 +12+48 Toon - 100g Also we knowo, Mmass of s Mi mass of trede) ? 22.42 of Vol. of agas o gubstance at STP at STP I and I alm. but we are provided Ry conditions at 298k & sahrs 5. to oud en . J substance ieat oc/243k now I NA no. of particles