Question

When Calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced.

CaCO₃(s) + 2HCl(aq)--------> CaCl₂(aq)+ H₂O(l)+ CO₂(g)

Determine the mass of CO₂ gas that forms when 20.0g CACO₃ (molar mass 100.07 g/mol) reacts with 3.0L 0.100M HCL.

Answer 1

first calculate limiting reagent

moles of HCl present = 0.100 x 3.0 = 0.3

according to balanced reaction

100.07 g CaCO3 reacts with 2 moles of HCl

20.0 g CaCO3 reacts with 20.0 x 2 / 100.07 = 0.40 moles HCl

but we have 0.3 moles HCl

so HCl is limiting reagent.

2 moles HCl gives 44 g CO2

0.300 moles HCl gives 0.300 x 44 / 2 = 6.6 g CO2

mass of CO2 formed = 6.60 g