The answer is first one.
In option B 3 moles of gas reacts with a mole of solid to form 3 moles of gas and 2 moles of solid. So the entropy can not be negative
In option C 2 moles of gas decomposes to 4 moles of two different gases.
In option D the phase transition from solid to liquid leads to increase entropy
In option E solid decomposes to gases
In option A 2 moles of gases forming two moles of different solid and liquid. So the entropy should be negative.
Question 1 For which one of the following reactions is ASº negative? Not yet answered Marked...
For which one of the following reactions is ASº negative? Select one: O a. 3 H2(g) + Fe2O3(s) → 2 Fe(s) + 3 H2O(g) O b. (NH4)2CO3(s) + 2 NH3(g) + H2O(g) + CO2(g) O c. 2 NO2(g) → N2(g) + 2 O2(g) O d. 2 IBr(g) → Iz(s) + Brz(4) o e. CoH6(s) → CoH6()
Calculate the enthalpy of reaction for the following reaction: Question 19 Not yet answered Marked out of 1.00 Fe2O3(s) + 3CO(g) – 2Fe(s) + 3C02(9) P Flag question AH °(Fe2O3(s)) = -824.2 kJ/mol AH°(CO(g)) = -110.5 AH°(Fe(s)) = ? AH°(CO2(g)) = -393.5 kJ/mol Answer:
Question 17 Not yet answered Calculate the enthalpy of reaction for the following reaction: 2Fe2O3(s) + 3C(s) - 4Fe(s) + 3CO2(g) Marked out of 1.00 Flag question AHI°(Fe2O3(s)) = -824.2 kJ/mol AH(C(s)) = ? AH®(Fe(s)) = ? AH(CO2(g)) = 3935 kJ/mol Answer:
37. Balance the following equations: a. PbO2(s) —>PbO(s) + O2(g) b. Fe(OH)3(s) —>Fe2O3(s) +H2O(s) C. (NH4)2CO3(s) —>NH3(g)+H20(g) + CO2(g) d. CaCl2(aq) + H2SO4(aq) — CaSO4(s) + HCl(aq) 761
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