Question

What mass (in g) of silver oxide, Ag₂O, is required to produce 27.2 g of silver sulfadiazine, AgC₁₀H₉N₄SO₂, from the reaction of silver oxide and sulfadiazine?

2 C₁₀H₁₀N₄SO₂ + Ag₂O → 2 AgC₁₀H₉N₄SO₂ + H₂O

A sample of 0.48 g of carbon dioxide was obtained by heating 1.24 g of calcium carbonate. What is the percent yield for this reaction?

CaCO₃(s) → CaO(s) + CO₂(s)

Determine the limiting reactant when 0.48 g of Cr and 0.72 g of H₃PO₄ react according to the following chemical equation. (Omit states-of-matter from your answer.)

2 Cr + 2 H₃PO₄ → 2 CrPO₄ + 3 H₂

What volume (in mL) of 0.0153 M HBr solution is required to titrate 125 mL of a 0.0131 M Ca(OH)₂ solution?

Ca(OH)₂(aq) + 2 HBr(aq) → CaBr₂(aq) + 2 H₂O(l)

What volume (in mL) of 0.09258 M HNO₃ is required to react completely with 0.2365 g of potassium hydrogen phosphate?

2 HNO₃(aq) + K₂HPO₄(aq) → H₃PO₄(aq) + 2 KNO₃(aq)

Answer 1

o q cIoHIO NU SO2 tag20 2 2 AgCOHqN4502 AgcoHqNa + H2O CloHioNuso 2 maar mass 100= 10712 = 120 10 H = 1oxol = 10 uns uxl4 = 56 1.5 = 1832 a 32 2001 = 2816. a 1132 250 * molar mass - 2348. * molar mass of A920=231.735g Imol. * molar mass of Ag Clo Hq NU SO2 = 0 cl 0 ll 32.00 Tag = .1X107.86 = 107.86 10 c = 10 x 12 = 120.00 H = 9xo1 uns uxlu is= 1x32 200) = 2X16 ? 32.00 , 356.86 231.735g/mol of Agzo gives 24356.868. of Ag clothq Nu 5O2 ag of Agro gives 27-29. of silver . sulfadiazine X x2x356.86 = 231.735 X27.2 first

231.7.35x2712 r = 2x 356.86 a= 6303.192 2x356.86 6303.192 713.72 Ice 8.8319.) onzorso

IN Đ caco 3 1.aug, of g cao + coz caco 3 gives = 0.489.002 ia.of coz о со со 3 x g. of coz 1.aug. Of cacez 2 ччR \ .4 (oo X2 г uuxlizy az 100 . as 54.50 [az.o.54 56g. Of com * This is theoritical yield of coo. actual yield = 0.48g, of cor (from Problem) percent yield = actual yield Theoretical yield * Xloo ou 8 x100 0.5456 = 0.8797 X100 percent yield s 87.97

acopou ts u + 3H2 qca + 2 H 3 pou 0.489 0.729. co-atomic mass = 51.99g. H3 pou molar mass =97.99 g Imol. Steph:- axs1.99g. of co= 3 molee of t2 0.48g of co of că "gémoly of H2 = 3X014.8 2x51.99xx as 3x0.48 2x51.99 ar l' lay 103.98 x =0.0138 moly, step.fr 2x 97.99 g. of H3pouz 3molep of H2 H3 pou = 36' mole of 6.72g. 2x9.7.99xa = 3X 0.72 x= 3x0.72 2x97.99 as 2016 495.98 Ta=0.ollmoles of H2